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Lubov Fominskaja [6]
3 years ago
5

Find the sum of the first 7 terms of the following sequence. Round to the nearest

Mathematics
1 answer:
gregori [183]3 years ago
8 0

Answer:

76454

Step-by-step explanation:

Sequence : 14,56,224, ..14(4^(n-1)

where n=term number.

First term: 14*(4^(1-1)) = 14*(4^0) = 14

Second term: 14*(4^(2-1))=14*4 = 56

Third term: 14*(4^(3-1))=14*16 = 224

...

7th term: 14*(4^(7-1)) = 14*(4^6)

Sum of the first 7 terms

= 14*(4^0+4^1+4^2+4^3+4^4+4^5+4^6)

= 14(4^7-1)/(4-1)

= 14(4^7-1)/3

= 76454

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NikAS [45]

Answer:

39

Step-by-step explanation:

Just add

7 0
3 years ago
What are the roots of the quadratic equation below 3x2+15x-5=0
fomenos

Answer:

<h2>A</h2><h2 />

Step-by-step explanation:

3x^2+15x-5=0\\a = 3\\b = 15\\c = -5\\ x = -b\±\frac{\sqrt{b^{2} -4ac} }{2a} \\x = -(15)\±\frac{\sqrt{15^{2} -4(3)(-5)} }{2(3)} \\x = -15 \±\frac{\sqrt{225+60} }{6} \\x = -15\±\frac{\sqrt{285} }{6} = A

8 0
3 years ago
You are given that cos(A)=−5/13, with A in Quadrant II, and sin(B)=7/25, with B in Quadrant II. Find cos(A+B). Give your answer
blsea [12.9K]

The value of cos(A+B) is 36/325.

<h3>What is Trigonometry?</h3>

The branch of mathematics concerned with specific functions of angles and their application to calculations.

Given:

cos(A)=−5/13

sin(B)=7/25

Now Using identity,

sin²A + cos² A= 1

sin A= √1 - cos² A

sin A = √1- 25/169

sin A= √144/169

sin A= 12/13

Again,

sin²B + cos² B= 1

cos B= √1 - sin² B

cos B = √1- 49/625

cos B= √576/625

cos B= -24/25

Now,

cos (A +B) = cos A cos B - sin A sin B.

= -5/13* (-24/25) - 12/13* 7/25

=  120/325 - 84/325

= 36/325

Hence, the value of cos (A + B) is 36/325.

Learn more about this concept here:

brainly.com/question/17056960

#SPJ1

3 0
2 years ago
A manager forecasts that 150 guests will be served tomorrow. The manager knows that one server can provide high quality service
iVinArrow [24]

Answer:

5 servers and 3 cooks(since a person doesn't exist in fraction)

Step-by-step explanation:

From the question provided above, the manager(who is obviously organizing some kind of party or get-togethers) is expecting a hindered and fifty guests in total .

And it also says that if a server can handle 30 guests and 150,how many of them are need?

Let X be number of servers needed:

X= 150/30 = 5 servers

AND

If a single cook can prepare meals for 60 guests,the number of cooks required to cover for 150 guest will be:

X= 150/60 = 2.5,but since a fraction of a human doesn't exist, we have to say that the manager needs 3 cooks(2 of them will handle a total of 120 guests and the other cook handles the 30 guests)

6 0
3 years ago
Plz help with this question
Anton [14]

Answer:

x + 5 = -4

x = -9

~theLocoCoco

5 0
3 years ago
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