There doesn't seem to be a question, but based on the topic above the question I would say, find the irrational numbers
Sorry I don't know man it could bed. I mean I am guessing.
Answer:
mRP = 125°
mQS = 125°
mPQR = 235°
mRPQ = 305°
Step-by-step explanation:
Given that
Then:
- measure of arc RP, mRP = mROP = 125°
Given that
- ∠QOS and ∠ROP are vertical angles
Then:
- measure of arc QS, mQS = mROP = 125°
Given that
- ∠QOR and ∠SOP are vertical angles
Then:
Given that
- The addition of all central angles of a circle is 360°
Then:
mQOS + mROP + mQOR + mSOP = 360°
250° + 2mQOR = 360°
mQOR = (360°- 250°)/2
mQOR = mSOP = 55°
And (QOR and SOP are central angles):
- measure of arc QR, mQR = mQOR = 55°
- measure of arc SP, mSP = mSOP = 55°
Finally:
measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°
measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°
Answer:
102 boxes.
Step-by-step explanation:
102x12=1224
The question says how many *full* boxes so even though the number is not exactly 1228, the correct answer is 102 boxes. Hope this helps!
