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2 years ago

I need help with this question I can’t figure it out

Mathematics

2 answers:

Aleksandr-060686 [28]2 years ago

3 0

Answer:

they are parallel

Step-by-step explanation:

they are parallel since their slope are equal

9/6 can be simplified to 3/2

blagie [28]2 years ago

3 0

Answer:

You're right; it's choice B parallel

Step-by-step explanation:

When it comes to two equations, when their slopes are the same, they are parallel. If the slopes are negatively reciprocated then they are perpendicular.

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What’s the answer for a, and b, and how would you solve it?

xxTIMURxx [149]

Answer:

a) negative

b) -7/6

Step-by-step explanation:

The x value increased, but the y value decreased so the line goes down and has a negative slope

(y₁-y₂)/(x₁-x₂) is the slope where (x₁,y₁) and (x₂,y₂) are points on the line

(4-(-3))/(-1-5)=7/-6

6 0

2 years ago

3.41 rounded to the nearest tenth please help

horrorfan [7]

Your answer would be 3.4

Anything under 5 it stays the same and anything over 5 it goes up one

5 0

2 years ago

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A car whose acceleration is constant reaches a speed of

Sergeu [11.5K]

Answer:

12.5 s

Step-by-step explanation:

If acceleration is constant, speed is proportional to time. To increase the speed by 50 km/h, the car will need an additional time given by ...

t/(50 km/h) = (20 s)/(80 km/h)

t = (20 s)(50/80) . . . . . multiply by 50 km/h

t = 12.5 s

It will take 12.5 more seconds for it to reach a speed of 130 km/h.

3 0

3 years ago

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Which statement best describes the polynomial?

amid [387]

Answer:-12 $x^{2}$ -9x-4584671418

Step-by-step explanation:

4 0

2 years ago

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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

2 years ago