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4 years ago

PLEASE SOLVE, ITS REALLY EASY, AND IM ON A TIMER..... EEEEEEE

Mathematics

1 answer:

mart [117]4 years ago

7 0

Answer:

What are the choices? How are we supposed to solve it? Seriously man

Step-by-step explanation:

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A bag contains 72 toffees. How many toffees can be stored in 122 such bags? Estimate the number of toffees to nearest tens.

d1i1m1o1n [39]

The exact number is 8,784 toffees but if you want me to estimate to the nearest tens then it would be 8,780

5 0

3 years ago

In the present formula what does i stand for?

timurjin [86]

answer:

Present value (PV) is an accounting term meaning the value today of some amount of money expected to be available one or more years in the future. ... In this formula, PV stands for present value, namely right now, in the year of analysis.

3 0

3 years ago

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

MA_775_DIABLO [31]

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

$d=11*\frac{32}{60}\\d= 5.87\ mi$

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

3 0

3 years ago

Here are the values of the first 5 terms of 3 sequences: : 30, 40, 50, 60, 70, . . . : 0, 5, 15, 30, 50, . . . : 1, 2, 4, 8, 16,

Levart [38]

Answer:

1,2,4,8,16.

Step-by-step explanation:

they are a square root of 2 for each question. it will eventually get up higher then additive.

4 0

3 years ago

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago