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Paraphin [41]
3 years ago
12

(Help fast plz!)Which statement is true regarding the graphed functions

Mathematics
1 answer:
Solnce55 [7]3 years ago
7 0

Given:

The graphs of two functions f(x) and g(x).

To find:

The correct statement about the functions.

Solution:

In the given graph blue line represents the graph of f(x) and the red line represents the graph of g(x).

From the given graphs it is clear that the graphs of the functions interest each other at point (-2,4). It means,

f(-2)=4

g(-2)=4

So, we conclude that

f(-2)=g(-2)

Thus the option D is correct.

We can check other options.

f(4)=-14

g(4)=10

f(4)\neq g(4)

So, option A is incorrect.

g(-2)=4

f(4)\neq g(-2)

So, option B is incorrect.

f(2)=-8

f(2)\neq g(-2)

So, option C is incorrect.

Therefore, the correct option is D.

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Point A is located at (-5, 2) on a coordinate grid. Point A is translated 8 units to the right and 3 units up to create point A.
Molodets [167]

The closest distance between point A and point A' is 8.5 ⇒ B

Step-by-step explanation:

Let us revise the translation of a point

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

∵ Point A is located at (-5 , 2)

∵ Point A is translated 8 units to the right and 3 units up

- That means add x-coordinate by 8 and add y-coordinate by 3

∴ Point A' located at (-5 + 8 , 2 + 3)

∴ Point A' located at (3 , 5)

The distance between two points (x_{1},y_{1}) and (x_{2},y_{2})

is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∵ Point a = (-5 , 2) and point A' = (3 , 5)

∴ x_{1} = -5 and x_{2} = 3

∴ y_{1} = 2 and y_{2} = 5

- Substitute these values in the rule of the distance

∵ d=\sqrt{(3--5)^{2}+(5-2)^{2}}

∴ d=\sqrt{(3+5)^{2}+(3)^{2}}

∴ d=\sqrt{(8)^{2}+(3)^{2}}

∴ d=\sqrt{64+9}=73

∴ d = 8.544 ≅ 8.5

The closest distance between point A and point A' is 8.5

Learn more:

You can learn more about the distance between two points in brainly.com/question/6564657

#LearnwithBrainly

5 0
4 years ago
Read 2 more answers
Can somebody help me <br> -2(x+5)
Anika [276]

Answer: -2x - 10

Steps: -2(x+5)

Apply the distributive law [ a(b + c) = ab + ac ]:

a = -2,  b = x,  c = 5

-2x + (-2) × 5

Apply minus/plus rules: -2x - 2 × 5

Multiply the numbers: 2 × 5 = 10

-2x - 10

Plz mark brainliest:)

5 0
3 years ago
Solve for p.<br> 4 - 3p = 22
yanalaym [24]

Greetings! Hope this helps!

Answer

p = -6

_____________

4 - 3p = 22

-4            -4

-3p = 18

/-3     /-3

p = -6

Have a good day!

_______________

A brainliest would help tons! :D

5 0
4 years ago
Solve for the value of x <br> A- 6<br> B- 16 <br> C- 100<br> D- 12
andreev551 [17]

The lines are parallel.

Theorem: If two parallel lines are cut by a transversal, then same side interior angles are supplementary.

The angles measuring 16x + 4 and 80 are supplementary, so thjeir measures add to 180.

16x + 4 + 80 = 180

16x + 84 = 180

16x = 96

x = 6

Answer:  A - 6

5 0
3 years ago
Problem 3
Murljashka [212]

Answer:

-\frac{2}{5}

Step-by-step explanation:

Given expression:

           2x + 5y = -10

The equation of a straight line is;

            y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

 Now;

          let us write the given expression in slope intercept format;

            2x + 5y  = -10

                    5y = -2x - 10

                     y = -\frac{2x}{5}  - 2

So, the slope of the line is -\frac{2}{5}

8 0
3 years ago
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