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3 years ago

Number 15 please logarithms algebra two

Mathematics

1 answer:

juin [17]3 years ago

5 0

Answer:

hope this helps

Step-by-step explanation:

look at the picture

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X/6=x/7-5 <br> Please show work thank you so much!!

stiv31 [10]

Step-by-step explanation:

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3 years ago

What is 3 divided by 11/12

Lena [83]

Answer:

0.02272

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone please help me with this one question

erastova [34]

the problem with this study is the fact that they used precise numbers

hope i helped:)

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3 years ago

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

Write n^4 • n^3 without exponents

Elis [28]

Answer:

n*n*n*n*n*n*n

Step-by-step explanation:

n^4 * n^3 = n^7 = n*n*n*n*n*n*n

8 0

3 years ago