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3 years ago

Can someone help me with my math I don't understand it

Mathematics

1 answer:

MArishka [77]3 years ago

6 0

Answer:

317°

Step-by-step explanation:

The total measure of the angles around the center of the circle is 360°. The sum of angles in each half (above AB or below AB) is half that, or 180°. So, the sum of angles below the line is 180°. We can use that fact to find x, then the measures of all of the angles.

(7x +1)° +90° +(9x -7)° = 180°

16x = 96 . . . . . divide by °, subtract 84

x = 6 . . . . . . . . divide by 16

Then angle AOD is ...

(7·6 +1)° = 43°

Short arc AD is 43°, so long arc ACD is 360° -43° = 317°.

arc ACD = 317°

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A sector of a circle has a central angle of 100 degrees. If the area of the sector is 50pi, what is the radius of the circle

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The radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is 6√5 units.

An area of a circle with two radii and an arc is referred to as a sector. The minor sector, which is the smaller section of the circle, and the major sector, which is the bigger component of the circle, are the two sectors that make up a circle.

Area of a Sector of a Circle = (θ/360°) πr², where r is the radius of the circle and θ is the sector angle, in degrees, that the arc at the center subtends.

In the question, we are asked to find the radius of the circle in which a sector has a central angle of 100° and the area of the sector is 50π.

From the given information, the area of the sector = 50π, the central angle, θ = 100°, and the radius r is unknown.

Substituting the known values in the formula Area of a Sector of a Circle = (θ/360°) πr², we get:

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or, r = √180 = 6√5.

Thus, the radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is 6√5 units.

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