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Black_prince [1.1K]
1 year ago
8

If rt is 10 centimeters long, what is st? 2 centimeters 4 centimeters 6 centimeters 8 centimeters

Mathematics
1 answer:
Ksju [112]1 year ago
8 0

Answer: I don’t know

Step-by-step explanation:

I don’t know

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8 divde by 1/6 equals 48 because<br><br>​
nika2105 [10]

Proof:

8\div\frac{1}{6}=\frac{8}{1}\div \frac{1}{6}=\frac{8}{1}\times\frac{6}{1}=\frac{8\times6}{1}=\frac{48}{1}=48 \\

6 0
3 years ago
Of the 1,640 students enrolled at a school, 50% come to school by bus, 35% come by car, and the rest of the students walk to sch
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Twenty minutes to work over the most would agree that your replying the i
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3 years ago
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HELP!!!
Jobisdone [24]

Answer:

16 is the number of quarters and 14 is the number of dimes

Step-by-step explanation:

we know that

1\ dime=\$0.10

1\ quarter=\$0.25

Let

x-----> the number of dimes

y------> the number of quarters

we know that

0.10x+0.25y=5.40 -----> equation A

x+y=30 ----Isolate the variable y

y=30-x -----> equation B

Substitute equation B in equation A

0.10x+0.25(30-x)=5.40      

0.10x+7.5-0.25x=5.40

0.25x-0.10x=7.5-5.40

0.15x=2.1

x=14\ dimes

Find the value of y

y=30-x

y=30-14=16\ quarters

therefore

16 is the number of quarters and 14 is the number of dimes

8 0
3 years ago
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The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.
fgiga [73]
The answer is <span>A. .357 + .372 + .350 + .349 + x = 1.754; .326 
</span>
x1 - average of <span>1999 Nomar Garciaparra Boston
</span>x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of <span>2001 Ichiro Suzuki Seattle 
</span>x4 - average of Manny Ramirez Boston  
x - average of <span>2003 Bill Mueller Boston 

</span><span>The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

<u>0.357 + 0.372 + 0.350 + 0.349 + x = 1.754</u>

1.428 + x = 1.754
x = 1.754 - 1.428
<u>x = 0.326</u></span>
5 0
3 years ago
[calculus] the distance from the point (6, -4) to the circle <img src="https://tex.z-dn.net/?f=x%5E2%2By%5E2-8y%3D0" id="TexForm
stealth61 [152]

Answer:

Option C.

The distance from the point to the circle is 6 units

Step-by-step explanation:

we know that

The distance between the circle and the point will be the difference of the distance of the point from the center of circle  and the radius of the circle

step 1

Find the center and radius of the circle

we have

x^{2} +y^{2}-8y=0

Convert to radius center form

Complete the square

x^{2} +(y^{2}-8y+16)=0+16

Rewrite as perfect squares

x^{2} +(y-4)^{2}=16

so

The center is the point (0,4)

The radius is

r^{2}=16\\r=4\ units

step 2

Find the distance of the point from the center of circle

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(6,-4) and (0,4)

substitute the values

d=\sqrt{(4+4)^{2}+(0-6)^{2}}

d=\sqrt{(8)^{2}+(-6)^{2}}

d=\sqrt{100}\ units

d=10\ units

step 3

Find the difference of the distance of the point from the center of circle  and the radius of the circle

10\ units-4\ units=6\ units

therefore

The distance from the point to the circle is 6 units

see the attached figure to better understand the problem

3 0
3 years ago
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