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anygoal [31]
3 years ago
14

Determine the slope of a line that goes through (2, 7) and (11, 10).

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer: 1/3

Step-by-step explanation: slope is the the difference of the y values over the x values.

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Which diagram shows parallel lines cut by a transversal? 2 lines are cut by a transversal. At the intersection of the first line
AlekseyPX

Answer:

c.

Step-by-step explanation:

2 lines are cut by a transversal. At the intersection of the first line with the transversal, the bottom right angle is 130 degrees. At the intersection of the second line with the transversal, the uppercase right angle is 50 degrees.

6 0
3 years ago
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Determine the values of a, b, and c for the quadratic equation<br><br> 3x2−5x+6=0
sweet-ann [11.9K]

Answer:

The values of a, b, and c for the quadratic equation

a=3

b=-5

c=6

7 0
3 years ago
Read 2 more answers
The lyric, "Historians research more than just the word of one/To learn all sides of history" most closely means that
Ymorist [56]

Answer:

I would say C

Step-by-step explanation:

I said C because when people look for information they look at different sources instead of just one.

8 0
3 years ago
if one angle in a pair of vertical angles measures 36degrees and the other measures (2n-8)degrees, which is the value of n ? ple
KiRa [710]

Answer:

n = 22

Step-by-step explanation:

Since they are vertical angles they are the same.

Therefore you can put together this equation:

2n - 8 = 36

Add 8 to both sides

2n = 44

Divide by 2

n = 22

8 0
4 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
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