YA

Pls help I<br> This is geometry Been struggling due soon show work

yawa3891 [41]

Triangles have $180^{\circ}$ in total, so the sum of all the angles should be $180^{\circ}$

First triangle

$180 = 90 + (x + 5) + (2x - 2)\\180 = 90 + x + 5 + 2x - 2\\180 - 90 - 5 + 2 = x + 2x\\87 = 3x\\x = 29^{\circ}$

Second triangle

$180 = (x + 40) + (2x - 5) + (3x - 17)\\180 = x + 40 + 2x - 5 + 3x - 17\\180 - 40 + 5 + 17 = x + 2x + 3x\\162 = 6x\\x = 27^{\circ}$

3 0

4 years ago

Read 2 more answers

Can someone help me with number 9. Solving for x using the Pythagorean’s theorem??

KatRina [158]

Answer:

29.75

Step-by-step explanation:

$37^{2} -22^{2} = x^{2}$

$x = 29.75$

5 0

4 years ago

How to solve equations

ankoles [38]

Answer:

It really depends on what type of equation you are solving.

However, if you're working with an equation that contains variables, it's advised that you should get rid of the variables first before the whole numbers/integers.

Step-by-step explanation:

4 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

you buy butter for $3.85 a pound one portion of onion compote requires 1.7oz of butter how much does the for butter for one port

DanielleElmas [232]

Answer:

hmmm

Step-by-step explanation:

hmmm

8 0

4 years ago