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Katena32 [7]
3 years ago
13

Otra forma de representar 42/9​

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

<em>42/9=14/3</em>

Step-by-step explanation:

<u>Simplificación de Fracciones</u>

Una fracción de la forma x/y puede ser representada de infinitas maneras, siempre y cuando produzcan el mismo resultado.

Por ejemplo, las fracciones 5/3 y 10/6 son equivalentes porque producen el mismo resultado. Obsérvese que tanto el numerador como el denominador en la segunda están multiplicados por 2.

Igualmente si tenemos 10/6, podemos obtener 5/3 dividiendo a ambos por 2.

La fracción 42/9 puede convertirse a una fracción equivalente dividiendo ambos términos por 3 para obtener 14/3

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Answer:

For part 6: 39

Step-by-step explanation:

You have your starting number and then it gets added to a product of two numbers. 8 + (2x2) = 12. 12 + (2x3) = 18. 18 + (3x3) = 27. 27 + (3x4) = 39. That is the most logical answer I was able to find.

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Kellens bill at a restaurant before tax and tip is $22 if tax is 5.25% and we wants to leave 15% of the bill including the tax o
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I don't get why I missed c I know why I missed the table can someone help me with c
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A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
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