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Vladimir79 [104]
3 years ago
7

Kellens bill at a restaurant before tax and tip is $22 if tax is 5.25% and we wants to leave 15% of the bill including the tax o

n for a tip how much will he spend in total
Mathematics
2 answers:
maxonik [38]3 years ago
4 0
26.62   you would have to multiply 22 by 0.0525  and then add that to 22 and  u would get 23.15, then you would have to multiply that by 0.15 and u would get 3.47 and then you would add 3.47 and 23.15 and you get 26.62 witch is the answer 

hope this helped 
Musya8 [376]3 years ago
3 0

22x0.0525 = 1.155

22 x 0.15 = 3.3 (tip)

22 + tax + tip = 26.46 (unless the tax is actually 11.55)

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What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ​ ( 3x 2 −4 2x+3 ​ )start fraction, d, divided by, d, x
stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1.

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}

\frac{d}{dx}(\frac{2x+3}{3x^2-4})

\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}

\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}

\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}

\frac{-6x^2-18x-8}{(3x^2-4)^2}

Therefore, our required derivative is \frac{-6x^2-18x-8}{(3x^2-4)^2}.

Now, we will substitute x=-1 in our derivative to find the required value as:

\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}

\frac{-6(1)+18-8}{(3(1)-4)^2}

\frac{-6+18-8}{(3-4)^2}

\frac{4}{(-1)^2}

\frac{4}{1}

4

Therefore, the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1 is 4.

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Answer:

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