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Vladimir79 [104]
3 years ago
7

Kellens bill at a restaurant before tax and tip is $22 if tax is 5.25% and we wants to leave 15% of the bill including the tax o

n for a tip how much will he spend in total
Mathematics
2 answers:
maxonik [38]3 years ago
4 0
26.62   you would have to multiply 22 by 0.0525  and then add that to 22 and  u would get 23.15, then you would have to multiply that by 0.15 and u would get 3.47 and then you would add 3.47 and 23.15 and you get 26.62 witch is the answer 

hope this helped 
Musya8 [376]3 years ago
3 0

22x0.0525 = 1.155

22 x 0.15 = 3.3 (tip)

22 + tax + tip = 26.46 (unless the tax is actually 11.55)

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Linda bought n packs of pencils. Each pack has 12 pencils. Write an equation to represent the total number of pencils p that Lin
arsen [322]

Answer:

p = 12n

Step-by-step explanation:

Given parameters:

     Number of pencils in each pack = 12 pencils

    Number of packs bought  = n

Unknown:

equation for total number of pencils, p = ?

Solution:

  Total number of pencils = number of pencils in each pack x number of packs bought

   Input parameters:

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           p = 12n

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5 0
3 years ago
Cushing's disease is characterized by muscular weakness due to adrenal or pituitary dysfunction. To provide effective treatment,
Katyanochek1 [597]

Answer:

Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Step-by-step explanation:

The given data is

Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80

∑ d= -579

 ∑d²= 29871

1) Let the hypotheses be

H0: ud= 25 against the claim    Ha: ud ≠25

H0 : mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Ha:   mean difference in the  age of onset of symptoms and age of diagnosis is not 25 months.

 

2) The degrees of freedom = n-1= 15-1= 14

3) The significance level is 0.05

4) The test statistic is

t= d`/sd/√n

The critical region is ║t║≤ t (0.025,14) = ±2.145

d`= ∑di/n= -579/15= -38.6

Sd= 23.178  (using calculators)

Therefore

t= d`/ sd/√n

t= -38.6/ 23.178√15

t= -1.655/3.872= -0.427

5) Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

8 0
3 years ago
A square garden plot measures 180 square feet. A second square garden plot measures 320 square feet. How many more feet of fence
REY [17]

The second garden plot will require 8√5 feet more fence than the first garden plot.

Further explanation:

In order to find the fence, we have to find the perimeter of both squares

So,

Area of Square 1: A1=180 square feet

Area of Square 2: A2=320 Square feet

Let x be the side of square 1:

Then,

A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}

For second square:

Let y be the side of second square

A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}

Perimeter of First Square:

P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet

Perimeter of Second Square:

P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet

The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.

P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet

The second garden plot will require 8√5 feet more fence than the first garden plot.

Keywords: Radicals, Operations on Radicals

Learn more about radicals at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

6 0
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Answer:

992,016

Step-by-step explanation:

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3 years ago
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