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ss7ja [257]
3 years ago
11

Translate the word phrase into a math expression.

Mathematics
1 answer:
algol133 years ago
4 0
I believe the answer is A
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A machine in a factor makes 2o gidgets every 1/4 hour. How many gidgets are made every hour ?
Dahasolnce [82]

Answer:

lol

Step-by-step explanation:

lollololol

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6 0
3 years ago
Prime factorization of 43
Volgvan

Answer:

Step-by-step explanation:

Prime factorization: 43 is prime. The exponent of prime number 43 is 1. Adding 1 to that exponent we get (1 + 1) = 2. Therefore 43 has exactly 2 factors.

8 0
2 years ago
Please help I asked this question earlier and nobody answered! :(​
tatiyna

Answer:

B

Step-by-step explanation:

One way to tell is to put both equations into slope-intercept form.  That form is usually written y=mx+b where  <em>m</em>  is the slope and  <em>b</em>  is the y-intercept.

Solve the first equation for y.

6x+2y=5 \\ 2y=-6x+5 \\ y=-3x+5/2

The slope of this line is -3, and its y-intercept is 5/2.

Solve the second equation for y.

y+3x=2\\y=-3x+2

The slope of this line is -3 and its y-intercept is 2.

The lines are parallel because they have the same slope and <u>different</u> y-intercepts.  There is no solution to the system.

8 0
3 years ago
What is the solution to the inequality -6( p - 8) &lt; -12?
coldgirl [10]

Answer:

p > 10

Step-by-step explanation:

Given

- 6(p - 8) < - 12

Divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.

p - 8 > 2 ( add 8 to both sides )

p > 10

3 0
3 years ago
Read 2 more answers
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
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