Hmm, I got these for roots:
0.7937053103356799
0.026855090968934903 +i* 1.6611004538114105
0.026855090968934903 -i* 1.6611004538114105
-6.84741549227355
Answer:
B:942$
Step-by-step explanation:
(pi*20^2)/2 is approximately 628.32
628.32*1.5=942.48
the end behavior of the function f(x)
the function f(x) must has odd number of roots ( where the graph of a function intersects the x-axis
the width cant be negative so the width of the rectangle would be 8 inches
<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,




- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;

- Hence, the number of 25 paise coins will be <u>12</u>.