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alukav5142 [94]

2 years ago

15

elizabeth has 10$, $5 and $1 dollar bills worth 101$. She has five more 5$ bills than 10$ bills and four times as many 1$ bills.

How many bills of each kind does elizabeth have?

2 answers:

Mumz [18]2 years ago

6 0

Answer:

The answer is 4 10$ bills, 9 5$ bills, and 16 1$ bills

vampirchik [111]2 years ago

4 0

$120 is your answer

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What is the factored form of the polynomial 27x2y-43xy2

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Answer:

xy(27x - 43y)

Step-by-step explanation:

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3 years ago

Evaluate y5 for y = 1.<br> 1<br> 5<br> 15

Sauron [17]

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8 0

3 years ago

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

Find the distance between (-4,3,-6) and the origin ((X,Y,Z) Graph)

devlian [24]

The distance between (-4,3,-6) and the origin is $\sqrt{61$

<h3>How to determine the distance?</h3>

The point is given as:

(x, y, z) = (-4,3,-6)

The origin is

(x, y, z) = (0,0,0)

The distance between the point and the origin is calculated as:

$d = \sqrt{x^2 + y^2 + z^2$

So, we have:

$d = \sqrt{(-4)^2 + (3)^2 + (-6)^2$

Evaluate

$d = \sqrt{61$

Hence, the distance between (-4,3,-6) and the origin is $\sqrt{61$

Read more about distance at:

brainly.com/question/7243416

#SPJ1

4 0

1 year ago