The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866
Answer:
99
Step-by-step explanation:
10% = 66
5% = 33
66+33=99
Answer:
sorry i can't understand your language ? please let me in English language ~_~
Answer:
The probability of spinning an even number is 1:2, or 50 percent. The probability of rolling an odd number is also 1:2, or 50 percent.
Explanation:
On most number spinners, there are an equal number of odds and evens. This is the same for a dice, since the numbers range from 1-6; 3 odd numbers and 3 even numbers.
Answer:
me
Step-by-step explanation:
what can I help to you