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3 years ago

10

Find the domain of the function X/

1 answer:

Ann [662]3 years ago

8 0

The domain<span> is all real numbers and the range is all real numbers f(</span>x) such that f(x<span>) ≥ 7. C) The </span>domain<span>is all real numbers </span>x<span> such that </span>x<span> ≥ 0 and the range is all real numbers. Incorrect. Negative values can be used for </span>x<span>, but the range is restricted because </span>x2<span> ≥ 0.</span>

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The cost for a pack of 8 padlocks is 19.20. Find the unit price in dollars per padlock. if necessary, round your answer to the n

muminat

19.2 / 8 = 2.4
$2.40 is your answer

5 0

3 years ago

Calculator display for<br> 1/9

KIM [24]

1/9 on a calculator is 0.11111111

5 0

2 years ago

Read 2 more answers

How to solve this question

Viefleur [7K]

Answer:

7x+21 = 7x + 21

Step-by-step explanation:

7(x+3)=6-(-7x - 15)

L.H.S

=7(x+3)

=7x+21 (multiply 7 by (x+3))

R.H.S:

=6-(-7x - 15)

= 6+7x+15 (multiply the -ive sign in the bracket)

= 7x + 21 ( adding 15 and 6)

now compare the two sides

7x+21 = 7x + 21 hence we prove that L.H.S= R.H.S

4 0

3 years ago

For any perfect square trinomial (quadratic), the constant term (last term) must be positive.

Ronch [10]

Answer:

For the perfect square trinomial (quadratic) i.e. $\left(x\:+\:3\right)^2$ , the constant term (last term) is positive.

Step-by-step explanation:

"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.

For example:

$\left(x\:+\:3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$a=x,\:\:b=3$

$=x^2+2x\cdot \:3+3^2$

$=x^2+6x+9$

Therefore, for the perfect square trinomial (quadratic) i.e. $\left(x\:+\:3\right)^2$ , the constant term (last term) is positive.

5 0

3 years ago

I am M I am a number between 17 and 25 I am a multiple of 36 is not a factor of mine what am I

Leni [432]

Answer:

wat

Step-by-step explanation:

8 0

2 years ago