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Oliga [24]
2 years ago
13

Solve for all missing measures

Mathematics
1 answer:
mylen [45]2 years ago
3 0

Answer:

Step-by-step explanation:

Begin

If this is a rhombus then <8 = 90 degrees as do all the central angles. That's because the diagonals intersect at right angles.

<4 = 38                   z formation for parallel lines.

<7 = 52                   The angles are part of a right angle triangle. <7 +38 = 90

<2 = 52                   z formation of parallel lines (a rhombus has ll lines).

<3 = 38                   The diagonals of a rhombus bisect each other.

<5 = 38                   z formation for parallel lines.

<6 = 52                   The diagonals of a rhombus are angle bisectors.

<1 = 52                     The diagonals of a rhombus are angle bisectors.

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Answer:

x = 1/2 and x = 9/2

Step-by-step explanation:

To solve this equation: |2x-5|=4 we need two evaluate two cases:

|2x-5| = 2x-5 when x>5/2 ✅

|2x-5| = -2x+5 when x<5/2✅

Then, if x>5/2:

2x-5 = 4 ➡ x = 9/2

Then, if x>5/2:

-2x+5 = 4 ➡ x = 1/2

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3 years ago
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What is the equation of the line perpendicular to the line y=4/9x-2 that passes through the point (4,3)?
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Solve the following problems : Given: S, T, and U are the midpoints of RP , PQ , and QR respectively. Prove: △SPT≅△UTQ.
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Answer:

Hence Proved △ SPT ≅ △ UTQ

Step-by-step explanation:

Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.

To prove: △ SPT ≅ △ UTQ

Proof:

∵ T is is the midpoint of PQ.

Hence PT = PQ    ⇒equation 1

Now,Midpoint theorem is given below;

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

By, Midpoint theorem;

TS║QR

Also, TS = \frac{1}{2} QR

Hence, TS = QU (U is the midpoint QR) ⇒ equation 2

Also by Midpoint theorem;

TU║PR

Also, TU = \frac{1}{2} PR

Hence, TU = PS (S is the midpoint QR) ⇒ equation 3

Now in △SPT and △UTQ.

PT = PQ (from equation 1)

TS = QU (from equation 2)

PS = TU (from equation 3)

By S.S.S Congruence Property,

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