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Natali5045456 [20]
3 years ago
11

A consulting firm submitted a bid for a large research project. The firm's management initially felt they had a 50-50 chance of

getting the project. However, the agency to which the bid was submitted subsequently requested additional information on the bid. Past experience indicates that for 80% of the successful bids and 35% of the unsuccessful bids the agency requested additional information. a. What is the prior probability of the bid being successful (that is, prior to the request for additional information)
Mathematics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

Probability = 0.50

Step-by-step explanation:

Given

Probability = 50\ 50\ chance  

Successful\ Bids = 80\%

Unsuccessful\ Bids = 35\%

Required

Determine the probability before the request of past experience

In this case, we only consider the 50 50 chance probability

Probability = \frac{50}{50 + 50}

Probability = \frac{50}{100}

Probability = 0.50

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3 years ago
1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?
prisoha [69]

Answer:

For this question, the options are written the wrong way. In each of the answers below, the correct form of the question will be added.  

The answers are:

1. e) 4/9

2. a) 1/16

3. 980 girls

4. c) 2/3

5. d) 1/13

6. a) 42 boys

7. d) 1/21

8. b) 1/6

Step-by-step explanation:

1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?

a) 4/3

b) 2/6

c) 4/6

d) 3/6

e) 4/9

The correct answer is e) 4/9 because the probability of getting a number greater than 2 in two rolls is 4/6 * 4/6 =16/36 = 4/9

2. A fair coin is tossed four times. What is the probability that it will be heads every time?

a) 1/16

b) 4/2

c) 2

d) 4/16

e) 1

The correct answer is a) 1/16 because the probability of each time that the coin is tossed is 1/2, and for 4 tosses is 1/2*1/2*1/2*1/2 = 1/16

3. The ratio of the number of girls to the number of boys was 2 to 5. If 2,450 students were present, how many were girls and how many were boys?

The correct answer is 980 girls, because 2450*2/5 = 980

4. A die is rolled twice. What is the probability of rolling a 5 or getting an even number?

a) 3/1

b) 1/12

c) 2/3

d) 1/3

If the die is rolled twice there are 12 possible outcomes and 8 of those outcomes can be 5 or an even number. The probability is 8/12 = 2/3

5. If one card is drawn from a standard deck, what is the probability of getting a jack?

a) 4/13

b) 1/52

c) 52

d) 1/13

e) 4

In a standard deck, there are 13 jack cards, the probability of getting a jack the first time is 1/13

6. There are 210 boys trying out for football. If 20% made the team, how many were chosen?

a) 42

b) 10

c) 4200

d) 105

e) 20

The number of boys that will be picked for the team is 210*20% = 42

7. From 42 boys who made the team, one will be chosen as kicker and one will be chosen as quarterback. What is the probability of being chosen as the kicker or the quarterback?

a) 2/21

b) 1/42

c) 2

d) 1/21

e) 42

The probability of getting picked for one of the 2 positions is 2/42 = 1/21

8. Two dice are rolled. There are 36 possible outcomes of rolling two dice. What is the probability of getting a total of seven on one roll?

a) 7

b) 1/6

c) 0

d) 7/36

e) 1/36

There are 6 ways of getting a sum of 7 tossing 2 dice, 1+6, 6+1, 2+5, 5+2, 3+4, 4+3. The probability is 6/36 = 1/6

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3 years ago
URGENT! 40 POINTS! PLEASE HELP!
umka2103 [35]

Answer:

(a) 8 x(5 x-6)=40 x^{2}-48 x

(c) \begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation 8 x(5 x-6)

8 x(5 x-6)=40 x^{2}-48 x

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation -4 x\left(2 x^{2}+1\right)

-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation (x-3)(5 x-6)

\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation(2 x+3)\left(x^{2}+3 x-5\right)

\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}

Hence, the given statement is false.

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Answer:

9

Step-by-step explanation:

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