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ruslelena [56]
4 years ago
6

player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to Player A, had 12 f

ewer runs batted in for the 2006 regular season. together, these two players brought home 248 runs during the 2006 regular season. How many runs batted did player A and player B each account for?
Mathematics
1 answer:
Nikitich [7]4 years ago
4 0
Let x be the number of batted runs for player A, then the number of batted runs for player B is x - 12

Given that both <span>players brought home 248 runs during the 2006 regular season, this means that

x + x - 12 = 248
2x = 248 - 12 = 236
x = 236 / 2 = 118.
</span>
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