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3 years ago

The temperature was 48°F and dropped 15° in two hours.

Mathematics

2 answers:

anyanavicka [17]3 years ago

8 0

Answer:

33 degrees Fahrenheit.

Step-by-step explanation:

If the temperature was 48 degrees, and it dropped 15, that means the initial temperature was subtracted by 15.

48 - 15 = 33.

VladimirAG [237]3 years ago

6 0

Answer:

33°F

Step-by-step explanation:

The initial temperature was 48°F. Then, it dropped by 15°.

I am assuming that both values are given in the same unit.

48 - 15 = 33

The temperature should be 33 degrees now.

Hope this helps.

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two numbered 1 to 6 dice are thrown together and their scores are added. the probability that the sum will be 4 is?

natulia [17]

Answer:

$Pr = \frac{3}{36}$

Step-by-step explanation:

Given

2 number die

Required

P(Sum = 4)

The sample space of 2 die is:

$S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)$

$(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6), (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)$

$(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)$

$n(S)= 36$

The pairs that adds up to 4 are:

$Sum(4) = \{(1,3), (2,2),(3,1)\}$

$n(Sum) =3$

So, the probability is:

$Pr = \frac{n(Sum)}{n(S)}$

$Pr = \frac{3}{36}$

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2 years ago

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2 years ago

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3 years ago

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solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

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3 years ago

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melisa1 [442]

Answer:

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3 years ago

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