Answer: She started with $160.
It will take 6 weeks before she has less than half of what she originally invested.
Step-by-step explanation:
If her money is decreasing in value by 11% each week, it means that the rate at which it is decreasing is exponential.
We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^t
Where
A represents the value of the investment after t weeks.
t represents the number of weeks.
P represents the initial value of the investment.
r represents rate of depreciation.
From the information given,
A = $142.40
r = 11% = 11/100 = 0.11
t = 1
Therefore
142.40 = P(1 - 0.11)^1
142.40 = P(0.89)
P = 142.4/0.89
P = 160
For her to have half of what she invested originally, then
80 = 160(0.89)^t
80/160 = (0.89)^t
0.5 = (0.89)^t
Taking log of both sides to base 10
Log 0.5 = log0.89^t = tlog0.89
- 0.3010 = - 0.051t
t = - 0.3010/- 0.051
t = 5.9
Approximately 6 weeks
Answer:
-23/22
Step-by-step explanation:
Slope m = (y2-y1)/(x2-x1)
m = (12 - 81)/(32 - -34) = (-69)/(66) = -23/22
The answer is 116631.6 if rounded it is 116632
Answer:
The solution in the attached figure
One possible solution is the point (30,60)
Step-by-step explanation:
Let
x -----> represents the number of tacos sold
y -----> represents the number of burritos sold
we know that
------> inequality A
-----> inequality B
using a graphing tool
The solution is the triangular shaded area
see the attached figure
One possible solution is the point (30,60)
Remember that if a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution
so
That means----> The number of tacos sold is 30 and the number of burritos sold
Verify
Substitute the value of x and the value of y in each inequality
Inequality A
----> is true
Inequality B
----> is true
The ordered pair satisfy both inequalities, then the ordered pair is a solution of the system
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Step-by-step explanation:
A ratio is the quantitative relation between two amounts showing the number of times one value contains or is contained within the other.
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