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slava [35]
3 years ago
10

What is the least common denominator of 4 and 10

Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Answer:

20

Step-by-step explanation:

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Consider two populations of coins, one of pennies and one of quarters. A random sample of 25 pennies was selected, and the mean
Alexus [3.1K]

Answer:

No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.

Step-by-step explanation:

"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"

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What is the percent of 19 and 5
Alexandra [31]
I think the answer should be 24
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3 years ago
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Solve 5x − 2(2x − 1) = 6
asambeis [7]
<h2><u><em>Answer:BRAINLIEST PLS</em></u></h2><h2><u><em>Ok so, the answer is</em></u></h2><h2><u><em>Step-by-step explanation:</em></u></h2><h2><u><em>Ok so, Let's solve your equation step-by-step.</em></u></h2><h2><u><em>5x−2(2x−1)=6</em></u></h2><h2><u><em>Step 1: Simplify both sides of the equation.</em></u></h2><h2><u><em>5x−2(2x−1)=6</em></u></h2><h2><u><em>5x+(−2)(2x)+(−2)(−1)=6(Distribute)</em></u></h2><h2><u><em>5x+−4x+2=6</em></u></h2><h2><u><em>(5x+−4x)+(2)=6(Combine Like Terms)</em></u></h2><h2><u><em>x+2=6</em></u></h2><h2><u><em>x+2=6</em></u></h2><h2><u><em>Step 2: Subtract 2 from both sides.</em></u></h2><h2><u><em>x+2−2=6−2</em></u></h2><h2><u><em>x=4</em></u></h2><h2><u><em>So, your answer would be:</em></u></h2><h2><u><em>x=4</em></u></h2>

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3 0
3 years ago
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Change 0.307 to a percent
Nookie1986 [14]
It would be 30.7% because when you change a decimal to a percent, the decimal point moves 2 places to the right. For a percent to a decimal, move the decimal point 2 places to the left
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1. Which expression is equal to 815-97?
lara [203]

Answer:

the answer is C.815+(-97)

Step-by-step explanation:

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