Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
Answer:
<em>C</em>
Explanation:
Option <em>A </em>is used for line spacing.
Option <em>B </em>is used for right indent.
Option <em>C</em> is used for right paragraph alignment.
Option <em>D</em> is used for bullet points.
The button used for paragraph alignment would be option <em>C</em>.
True, sites such as kickstarter and just giving are fantastic examples of such.
Answer:
From the given diagram, consider a MIN node whose children are terminal nodes, if MIN plays
suboptimal. MIN will never be lower than the utility obtained playing against an optimal MIN
MIN will always select a move having minimax utility greater than or equal to the move that is
predicted by the minimax that is the MIN-played optimal value.
Then the MIN node's value is increased to MAX. This is done by induction.
One can do better than the minimax strategy, if the suboptimal play is predicted by MIN.
If MIN always falls for certain for certain kind of trap and losses, then setting up a trap guarantees a win.
Explanation:
See attached picture also.