Answer:
4 classes
Step-by-step explanation:
4+3+5+9+3+4=28
28/6=4.6
What's the first and third quartile of -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 7, 7, 7
jek_recluse [69]
There are 14 total numbers.
Make a list of the 7 lowest numbers:
-5, -4, -3, -2, -1, 0 , 1
The first quartile is the middle value of the lower half of numbers
Since there are 7 numbers ( odd number), the middle value is the middle number, which is -2
Now make a list of the 7 highest numbers:
2, 3 , 4, 5 , 7, 7, 7
The 3rd quartile is the middle value of the higher half of numbers.
Again because there are 7 numbers ( odd number), the middle value is the middle number, which would be 5.
First quartile = -2
Third quartile = 5
Answer:
S
Step-by-step explanation:
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Answers:
- Vertex form: y = -2(x-1)^2 + 8
- Standard form: y = -2x^2 + 4x + 6
Pick whichever form you prefer.
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Explanation:
The vertex is the highest point in this case, which is located at (1,8).
In general, the vertex is (h,k). So we have h = 1 and k = 8.
One root of this parabola is (-1,0). So we'll plug x = -1 and y = 0 in as well. As an alternative, you can go for (x,y) = (3,0) instead.
Plug those four values mentioned into the equation below. Solve for 'a'.
y = a(x-h)^2 + k
0 = a(-1-1)^2+8
0 = a(-2)^2+8
0 = 4a+8
4a+8 = 0
4a = -8
a = -8/4
a = -2
The vertex form of this parabola is y = -2(x-1)^2+8
Expanding that out gets us the following
y = -2(x-1)^2+8
y = -2(x^2-2x+1)+8
y = -2x^2+4x-2+8
y = -2x^2+4x+6 .... equation in standard form
