I dont understand how to explain this.

Mathematics

1 answer:

podryga [215]3 years ago

6 0

Answer:

Angle F is 50° because their side lengths are different but the angle measurements did not change. All triangles add up to 180 degrees and a right angle is 90 and it gives you the other angle measurement. So you would do 40 plus 90 which would get you 130. To find the last angle you would do 180 minus 130 which is 50. Angle F is 50 degrees.

Step-by-step explanation:

this is what i would say

You might be interested in

Can you please help me because I can’t do it right

Dovator [93]

12% growth

12% decay

20% decay

22% growth

8 0

3 years ago

HELP PLS use the original price and markup to find the retail price. original price $68 markup 20%

insens350 [35]

Answer: $81.60

Step-by-step explanation:

When we have an original price OP, and a markup of X% (this is how much increases the price with respect to the original price)

The retail price will be:

RP = OP + (X%/100%)*OP

RP = OP*(1 + X%/100%)

In this case, we have:

Original price = OP = $68

markup = X% = 20%

Replacing these in the above equation, we get:

RP= $68*(1 + 20%/100%) = $68*(1 + 0.20)

RP = $68*(1.20) = $81.60

Then the retail price of this particular item is $81.60

4 0

3 years ago

Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?

harina [27]

$\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}$

now with that template in mind

$\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill$