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Ber [7]
3 years ago
10

Find the solution of 2/3x+1/4=-4/3

Mathematics
1 answer:
wolverine [178]3 years ago
6 0
These questions can be daunting at first, but they're pretty simple to solve.

First, we need to establish a common denominator.  We have 2 / 3, 1 / 4, and
-4 / 3.  The least common denominator we can get is by multiplying 4 and 3 together to get 12.  So we will change the denominator as follows;

2 / 3, 1 / 4, -4 / 3  =  8 / 12, 3 / 12, -16 / 12

Now we can put these back into the equation.

8/12x + 3/12 = -16/12
8x + 3 = -16

It's simple math from here on out, but I'll show the process.  What we can basically do now is take away the denominator because it doesn't matter now that it's common.

Subtract 3 from both sides.  Now we have 8x = -19

Dividing by 8 on both sides of the equation will get you your answer.

x = -19/8


Hope this helps!
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Estimate the sum 11 3/8 + 9 7/10 + 21 1/4 by rounding each mixed number to the nearest whole number. Then find the exact sum
vodka [1.7K]
Answer:
Approximately 42.
Exact sum is 42 13/40.

Explanation:
Estimate 11 3/8: 11
Estimate 9 7/10: 10
Estimate 21 1/4: 21
Add them together: 42.

11.375 + 9.7 + 21.25 = 42.325
I made them into decimals and then will convert it into fraction.
42.325 = 42 13/40

Hope this helps!
3 0
3 years ago
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Ostrovityanka [42]
Multiply the number of peaches by the number of pounds and add the number of pounds and multiply 1.35 by the number of pounds that you added up
5 0
3 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
Solve for 5 points, will give brainlist
Elanso [62]

Answer:

i know that the first one is not equivlent but i dont know about the others

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

x-intercept => point (2, 0)

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8 0
3 years ago
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