1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
Answer:
2a=1/2
a=1/4
Step-by-step explanation:
Answer: x y
-2 15
-1 9
0 7
1 9
2 15
3 25
Step-by-step explanation:you always do the exponent first, then you multiply that by that two, and then you add 7.
The last one is not necessarily true
Answer:
51
Step-by-step explanation:
90-39 = 51
