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3 years ago

Please help. i have 20 minutes left

Mathematics

1 answer:

ololo11 [35]3 years ago

5 0

Answer:

You need to insert different x values and plot the point. So let's say x=1 the answer would be 10 and for 2 it would be 17

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How do you do this question?

likoan [24]

Answer:

a) -7/9

b) 16 / (n² + 15n + 56)

c) 1

Step-by-step explanation:

When n = 1, there is only one term in the series, so a₁ = s₁.

a₁ = (1 − 8) / (1 + 8)

a₁ = -7/9

The sum of the first n terms is equal to the sum of the first n−1 terms plus the nth term.

sₙ = sₙ₋₁ + aₙ

(n − 8) / (n + 8) = (n − 1 − 8) / (n − 1 + 8) + aₙ

(n − 8) / (n + 8) = (n − 9) / (n + 7) + aₙ

aₙ = (n − 8) / (n + 8) − (n − 9) / (n + 7)

If you wish, you can simplify by finding the common denominator.

aₙ = [(n − 8) (n + 7) − (n − 9) (n + 8)] / [(n + 8) (n + 7)]

aₙ = [n² − n − 56 − (n² − n − 72)] / (n² + 15n + 56)

aₙ = 16 / (n² + 15n + 56)

The infinite sum is:

∑₁°° aₙ = lim(n→∞) sₙ

∑₁°° aₙ = lim(n→∞) (n − 8) / (n + 8)

∑₁°° aₙ = 1

8 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Which equation can be used to solve the problem 180 is 40% of what number

Kruka [31]

Answer:

40/100 * x = 40

Solve for x. Hope this helps

6 0

3 years ago

Read 2 more answers

Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4

fomenos

Answer:

x g(x)

1 −10

2 −12

3 −14

Step-by-step explanation:

Substitute the values and do the arithmetic.

Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.

f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic

g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice

6 0

3 years ago

Hiroto spends \$68 on e-books and paperback books combined. Each e-book he buys costs $5 and each paperback book he buys costs $

alina1380 [7]

The equation that can be used to model the situation regarding the e-books and paperback is 5x + 12y = 68

The following information can be gotten from the question:

Total amount spent on e-books and paperback = $68

Cost of e-book = $5 each.

Cost of paperback = $12 each

Number of e-books = x

Number of paperbacks = y

Therefore, the equation that can be used to model the situation regarding the e-books and paperback will be:

= 5(x) + 12(y) = 68

5x + 12y = 68

The equation will be 5x + 12y = 68

Read related link on:

brainly.com/question/25212173

5 0

2 years ago