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seropon [69]
3 years ago
15

Factorise y^3- 7y+6 ​

Mathematics
2 answers:
Tatiana [17]3 years ago
4 0

Answer:

(y−1)(y−2)(y+3)

Step-by-step explanation:

Factor y3−7y+6

y3−7y+6

=(y−1)(y−2)(y+3)

prisoha [69]3 years ago
3 0

Answer:

(y - 2) (y-1) (y+3)

Step-by-step explanation:

y³-7y+6

= y³ +2y² - 2y² - 3y - 4y +6

= ( y³ +2y² - 3y) - (2y² + 4y -6)

= y( y² +2y -3) - 2( y² + 2y -3)

= (y² +2y -3)(y-2)

= ( y² +3y -y -3)(y-2)

= [ y( y+3) -(y+3)] ( y-2)

= (y-1)(y+3)(y-2)

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