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3 years ago

Sorting an excel table

Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

Sort data in a table

Select a cell within the data.

Select Home > Sort & Filter. Or, select Data > Sort.

Select an option: Sort A to Z - sorts the selected column in an ascending order. Sort Z to A - sorts the selected column in a descending order. Custom Sort - sorts data in multiple columns by applying different sort criteria.

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HELP I NEED HELP ASAP

ValentinkaMS [17]

Answer: a

Step-by-step explanation:

6 0

3 years ago

15 points!!!!!help!!!!!!!!!!!!

Setler [38]

Hi! :)

So a right triangle is a triangle that contains a ninety degree angle, it's not classified by side length. A scalene triangle is a triangle in which all three sides are different lengths. An isosceles triangle has two sides that are the same length. Either a scalene or an isosceles triangle could contain a right angle, so your answer is yes.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Which equation has infinitely many solutions? A) 4x + 3 3 = 4x + 5 B) 10x + 8 2 = 5x + 4 C) 8x − 5 3 = 2x − 2 D) 8x − 5 2 = 4x −

abruzzese [7]

Answer: If the left side and the right side of the equation are equal, the equations has infinitely many solutions.

Step-by-step explanation:

The options are not clear, so I will give you a general explanation of the procedure you can use to solve this exercise.

The Slope-Intercept form of the equation of a line is the following:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

For this exercise you need to remember that, given a System of Linear equations, if they are exactly the same line, then the System of equations has Infinitely many solutions.

If you have the following system:

$\left \{ {{y=2x+1} \atop {y=\frac{12}{6}x+1}} \right.$

You can simplify the second one:

$y=2x+1$

Then, both equations are the same line.

By definition you can also write the systemf making both equations equal to each other:

$2x+1=2x+1$

So, if the left side and the right side are equal, the equations has infinitely many solutions.

3 0

3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

Write eight ten thousands, five hundreds, two tens, seven ones

Alecsey [184]

THE ANSWER IS 80,527

6 0

3 years ago