E volume of the object, when you reduce the length of your ruler by a factor of 8, the number of volume elements increases by
a factor of 512 what's the dimension
2 answers:
Answer:
.88
Step-by-step explanation:
We can use this equation:
![N=R^{D}](https://tex.z-dn.net/?f=N%3DR%5E%7BD%7D)
Where:
- N is the increase factor (N=512)
- R is the reduce factor (R=8)
- D is the dimension
![512=5^{D}](https://tex.z-dn.net/?f=512%3D5%5E%7BD%7D)
We just need to solve it for D
![D=log(512)/log(5)](https://tex.z-dn.net/?f=D%3Dlog%28512%29%2Flog%285%29)
.88
Therefore the dimension will be 3
I hope it helps you!
Answer:
The dimension is 4
Step-by-step explanation:
Using the equation
N = R^d
Where,
N is the increase factor = 512
R is the reduce factor = 8
d is the dimension
512 = 5^d
Solving by logarithm
1log 512 = d log 5
D = log 512 ÷ log 5
= 3.87
Approximately 4
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