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2 years ago

I NEED HELP ASAP!!!!!

Mathematics

1 answer:

sveta [45]2 years ago

6 0

Angle 1 is also 54. 2 and 4 are verticals. 4 is 126

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What is the true solution to the logarithmic equation below?

Oliga [24]

Answer:

x = 2

Step-by-step explanation:

<u>Given:</u>

log ₄ (2x) = 1

<u>Solving for x:</u>

2x = 4¹
2x = 4
x = 2

3 0

2 years ago

A tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an initial speed of 120 feet per secon

Makovka662 [10]

Answer:

The maximum height is reached after 3.75 seconds.

Step-by-step explanation:

Assuming the deceleration due to gravity is unaided by air resistance, gravity causes the ball to lose vertical speed at the rate of 32 ft/s every second. The initial vertical speed of 120 ft/s will decline to zero when t satisfies ...

... 120 ft/s - (32 ft/s²)t = 0

... (120 ft/s)/(32 ft/s²) = t = 3.75 s

The ball will not go any higher after its vertical speed is zero.

6 0

2 years ago

find the value of the trigonometric function sin (t) if sec t = -4/3 and the terminal side of angle t lies in quadrant II

kodGreya [7K]

Answer:

$sin(t) =\frac{\sqrt{7}}{4}$

Step-by-step explanation:

By definition we know that

$sec(t) = \frac{1}{cos(t)}$

and

$cos ^ 2(t) = 1-sin ^ 2(t)$

As $sec(t) = -\frac{4}{3}$

Then

$sec(t) = -\frac{4}{3}\\\\\frac{1}{cos(t)} =-\frac{4}{3}\\\\cos(t) = -\frac{3}{4}$

Now square both sides of the equation:

$cos^2(t) = (-\frac{3}{4})^2$

$cos^2(t) = \frac{9}{16}\\\\$

$1-sin^2(t) =\frac{9}{16}\\\\sin^2(t) =1-\frac{9}{16}\\\\sin^2(t) =\frac{7}{16}\\\\sin(t) =\±\sqrt{\frac{7}{16}}$

In the second quadrant sin (t) is positive. Then we take the positive root

$sin(t) =\sqrt{\frac{7}{16}}$

$sin(t) =\frac{\sqrt{7}}{4}$

8 0

2 years ago

Five married couples have bought 10 seats in the same row for a concert. In how many different ways can they be seated (a) with

OverLord2011 [107]

a) 10! b)5!.2!.2!.2!.2!.2! c) 5!.2!

4 0

3 years ago

NO LINKS !!!!

Soloha48 [4]

Hello isania. the answer is B and E.

8 0

2 years ago