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Advocard [28]
3 years ago
15

Are the expressions 1 1/4c and 1.25c the same

Mathematics
1 answer:
liubo4ka [24]3 years ago
5 0

Answer:

the answer is 1768656

Step-by-step explanation:

1+1=1

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Answer:

34

Step-by-step explanation:

xzzee#^€^€€%^"$~~×

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X=11 because u Solve for the first variable in one of the equations, then substitute the result into the other equation.
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A cube block has sides 8cm long. A cylindrical hole of radius 3.6 is drilled through the block. Find the volume of the block tha
djverab [1.8K]

Answer:

186.45 cm^3

Step-by-step explanation:

Given data

Side lenght of cube block= 8cm

Radius of cylindrical hole= 3.6cm

Volume of entire Shape= l^3

Volume of entire Shape= 8*8*8

Volume of entire block= 512cm^3

Volume of cylindrical hole= πr^2h

Volume of cylindrical hole= 3.14*3.6^2*8

Volume of cylindrical hole= 3.14*12.96*8

Volume of cylindrical hole= 325.55cm^3

Hence the volume of the block

=volume of entire shape- volume of cylinder

=512-325.55

=186.45 cm^3

7 0
3 years ago
An object falls 9 meters during the first second, another 27 meters during the second second, and then 81 meters more during the
marishachu [46]
360 meters is the answer as 9 meter in 1st second ,27 meter in 2nd and 81 in 3rd it is in a series of geometric progression ...of 9,27,81 in which 9*3 =27,27*3=81 so next number will be 81*3=243 total distance moved in 4 seconds is 243+81+27+9=360 meters

4 0
3 years ago
A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th
ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0
3 years ago
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