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Advocard [28]
3 years ago
13

200 + O2 → 2CO2

Chemistry
1 answer:
Ugo [173]3 years ago
4 0

<em>ANSWER 10 MOLES OF CARBON DIOXIDE</em>

2C0 + O2 → 2CO2

2 moles of carbon monoxide forming 2 moles of carbon dioxide

10 moles of carbon monoxide will form 10 moles of carbon dioxide

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QUESTION 3
ohaa [14]

The result would be: loss of farmland

5 0
3 years ago
Calculate the density in g/l of co2 gas at 27 Celsius and 0.500 atm pressure
lesya692 [45]

Answer:

The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 \frac{grams}{L}

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

<u><em>P*V = n*R*T  Equation (A)</em></u>

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

Density allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

Being the molar mass of a substance the mass contained in one mole of said substance, the number of moles can be expressed as:

n=\frac{mass}{molar mass} <em>Equation (B)</em>

Replacing in <u><em>Equation (A)</em></u>:

P*V=\frac{mass}{molar mass} *R*T

Solving to get the definition of density expressed in the equation, you get:

density=\frac{mass}{V} =\frac{P*molar mass}{R*T}

Being:

  • P=0.500 atm
  • Molar mass CO₂= 44 g/mole
  • R= 0.082 \frac{atm*L}{mole*K}
  • T= 27 C= 300 K (being 0 C=273 K)

and replacing:

density=\frac{mass}{V} =\frac{0.500 atm*44 \frac{g}{mole} }{0.082 \frac{atm*L}{mole*K} *300 K}

you get:

density= 0.89 \frac{grams}{L}

<em><u>The density of CO₂ gas at 27 Celsius and 0.500 atm is 0.89 </u></em>\frac{grams}{L}<em><u></u></em>

3 0
4 years ago
Calculate the PH of a solution 0.030 MH2SO4
Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

4 0
3 years ago
Calculate the new pressure if a 2300 mL of a gas at a pressure of 1.88 atm is allowed to contract to a volume of 2.21 L.
olya-2409 [2.1K]

Answer:

V₂ = 0.958 atm

Explanation:

Given data:

Initial volume = 2300 mL (2300/1000 = 2.3 L)

Initial pressure = 1.88 atm

Final volume = (2.21 L + 2.3L) = 4.51 L

Final pressure = ?

Solution;

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.88 atm × 2.3 L =  P₂ × 4.51 L

V₂ = 1.88 atm × 2.3 L / 4.51 L

V₂ = 4.32 atm.L /  4.51 L

V₂ = 0.958 atm

6 0
3 years ago
Which of the following is an example of a chemical change? (Select all that apply).
Irina18 [472]

Answer:

Baking soda and vinegar combine and bubbles (a gas) are produced

Two liquids combine to form a solid substance

A match burns

Explanation:

6 0
3 years ago
Read 2 more answers
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