To determine the amount of oxygen that is present in the compound, we have to assume that the given compound contains carbon, hydrogen and oxygen only or else we will not be able to determine the answer. We need to convert the moles of the elements given to units of grams by using the atomic mass of these elements. Then, from the total amount of the compound we subtract the masses of the elements. We do as follows:
mass
0.117 mol C ( 12.01 g / 1 mol ) = 1.41 g
0.233 mol H ( 1.01 g / 1 mol ) = 0.24 g
Mass O = 3.50 g - 1.41 g - 0.24 g = 1.85 g O
Moles O = 1.85 g O ( 1 mol / 16 g ) = 0.116 moles O
D, because matter does not change in space but unlike gravity, which changes, matter, is the mass of it, which will stay the same unless there is a chemical change or, physical change, but not in this case, so the answer you are looking for is D. hope this enlarged your understanding and knowledge.
All you need to do is change 5% into a decimal which would be 5/100 = .05
then multiply the decimal by the total volume to get the amount of active ingredients in ml
.05 * 56ml = 2.8 ml of active ingredient.
Hope that helps!
Answer:
0.03697 mol Al₂(SO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
12.65 g Al₂(SO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Al - 26.98 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol
<u>Step 3: Convert</u>
<u />
= 0.03697 mol Al₂(SO₄)₃
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
We already have 4 sig figs in the final answer, so no need to round.
Answer:
C is the answer hoped I helped you have a awesome day by
