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STatiana [176]
4 years ago
12

I need to do a project about carbon dioxide is there a safe way to capture it ??/

Chemistry
1 answer:
kramer4 years ago
3 0
Yes. Exhale into a jar.
That's a hella ratchet way to capture CO2, but it works nonetheless
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The radioactive isotope tritium decays with a first-order rate constant k of 0.056 year-1. what fraction of the tritium initiall
algol [13]
Does this involve half lives
3 0
4 years ago
How many moles are in 23.8 g of sulfur dioxide
Yuki888 [10]

Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

hope it helps :)

4 0
2 years ago
What type of bond is formed between metal ions and nonmetal ions?
Lostsunrise [7]
Ionic is metal and nonmetal
5 0
3 years ago
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Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Hf = –296.8 kJ/mol) according to the equation below.
Pavel [41]
Given that the reactants are the very consituents (elements)  of the final compound, the enthalpy change of this reaction is the same  heat of formation, Hf.

That means that the enthalpy chage for the reaction is -296.8 kj/mol
7 0
3 years ago
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Chromium-51 is a radioisotope that is used to assess the lifetime of red blood cells The half-life of chromium-51 is 27.7 days.
8090 [49]

Answer:

11.9g remains after 48.2 days

Explanation:

All isotope decay follows the equation:

ln [A] = -kt + ln [A]₀

<em>Where [A] is actual amount of the isotope after time t, k is decay constant and [A]₀ the initial amount of the isotope</em>

We can find k from half-life as follows:

k = ln 2 / Half-Life

k = ln2 / 27.7 days

k = 0.025 days⁻¹

t = 48.2 days

[A]  = ?

[A]₀ = 39.7mg

ln [A] = -0.025 days⁻¹*48.2 days + ln [39.7mg]

ln[A] = 2.476

[A] = 11.9g remains after 48.2 days

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8 0
4 years ago
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