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postnew [5]
2 years ago
15

How many liters of fat would have to be removed to result in a 5.2 lb weight loss? The density of human fat is 0.94 g/mL?​

Chemistry
1 answer:
aksik [14]2 years ago
7 0
I don’t even know I’m just answering for pints
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Find the number of moles of water that can be formed if you have 138 mol of hydrogen gas and 64 mol of oxygen gas.
charle [14.2K]
2H₂₍g₎ + O₂ ₍g₎→ 2H₂O

138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O

128 mol H₂O
6 0
3 years ago
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What are the coefficients that would balance this equation _____NaOH+____H2CO3-Na2CO3+_____H2O
FromTheMoon [43]
I don’t see any equal signs to make it an equation. Am I missing something?
4 0
2 years ago
20 points! Help please
Olin [163]

Answer: 2N2O3 -> 2N2 + 3O2

Explanation:

5 0
2 years ago
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When a teacher dilutes 50 mL of 2.0 M NaOH to 0.50 M, what volume of NaOH results?
JulijaS [17]

Answer:

= 200 mL

Explanation:

Using the dilution formula;

M1V1 = M2V2 ;

Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.

M1 = 2.0 M

V1 = 50 mL

M2 = 0.50 M

V2 = ?

V2 = M1V1/M2

     = ( 2.0 × 50 )/ 0.5

     = 200 mL

Therefore, the volume after dilution will be, 200 mL

6 0
3 years ago
Hydrogen is manufactured on an industrial scale by this sequence of reactions:
hichkok12 [17]

Answer:

K=K_1*K_2\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}

Explanation:

Hello there!

In this case, for the given chemical reaction, it turns out firstly necessary to write the equilibrium expression for both reactions 1 and 2:

K_1=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \\\\K_2=\frac{[CO_2][H_2]}{[CO][H_2O]}

Now, when we combine them to get the overall expression, we infer these two are multiplied to get:

K=K_1*K_2\\\\K=\frac{[CO][H_2]^3}{[CH_4][H_2O]} *\frac{[CO_2][H_2]}{[CO][H_2O]}\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}

Regards!

6 0
3 years ago
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