All categories

3 years ago

Which relationship describes angles 1 and 2?

Mathematics

1 answer:

Fudgin [204]3 years ago

3 0

Answer:

2 and then 1

Step-by-step explanation: 1 is the slideing line that goes up to down and 2 is the angle that goes left & right (thats all i can exsplain sorry ;( )

You might be interested in

Please help i need help please

posledela

Answer:

Step-by-step explanation:

7 0

2 years ago

Which function is the inverse of f(x) = 2x + 3?

Gnesinka [82]

Answer:

f(x inv)=-1/2x-3

Step-by-step explanation:

You pretty much just have to flip all the numbers to fractions and all the positives to negatives.

6 0

2 years ago

The gym teacher is setting up for a field

irinina [24]

$630

The total perimeter is 42 and 42x15=630

7 0

2 years ago

Suppose a triangle has sides 3, 4, and 6. Which of the following must be true? A: The triangle in question is not a right triang

Talja [164]

Answer:

A: The triangle in question is not a right triangle.

Step-by-step explanation:

If the triangle is a right triangle, then the Pythagorean theorem would hold

a^2 + b^2 = c^2

3^2 + 4^2 = 6^2

9+16 = 36

25 = 36

This is not true so this is not a right triangle

7 0

3 years ago

Read 2 more answers

Plz help with equation of the circle will award fastest CORRECT answer with brainliest

aliina [53]

Answer:

$(x-1)^2+(y-2)^2=6.25$

Step-by-step explanation:

The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let (1,2) be x₁ and y₁ and let (2.5,4) be x₂ and y₂. Therefore:

$d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5$

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25$

3 0

3 years ago