Answer:
(p^2−6) (1-q(p^2-6))
Step-by-step explanation:
p^2−6−q·(p^2−6)^2
Put parentheses around the P^2-6 at the beginning of the expression
(p^2-6) -q (p^2−6)^2
Factor out (p^2−6)
(p^2−6) (1-q(p^2-6))
first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.
let's notice the vertex, or U-turn, is at (-2, 2)
![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2](https://tex.z-dn.net/?f=%20%5Cbf%20~~~~~~%5Ctextit%7Bparabola%20vertex%20form%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cboxed%7By%3Da%28x-%20h%29%5E2%2B%20k%7D%5C%5C%5C%5C%20x%3Da%28y-%20k%29%5E2%2B%20h%20%5Cend%7Barray%7D%20%5Cqquad%5Cqquad%20vertex~~%28%5Cstackrel%7B-2%7D%7B%20h%7D%2C%5Cstackrel%7B2%7D%7B%20k%7D%29%20%5C%5C%5C%5C%5C%5C%20y%3D%2B1%5Bx-%28-2%29%5D%5E2%2B2%5Cimplies%20y%3D%28x%2B2%29%5E2%2B2%20)
Answer:
Step-by-step explanation:
Slope is 0
Answer:

Step-by-step explanation:

<, > - open circle
≤, ≥ - closed circle
<, ≤ - draw the line to the left
>, ≥ - draw the line to the right
If you let x = 13:
Then, Area = 2(13)^2 - 5(13)
= 338 - 65
= 273 sq ft
If you let 2x-5 = 13:
2x = 18
x = 6
Then, Area = 2(6)^2 - 5(6)
= 72 - 30
= 42 sq ft
Therefore, your options are A or C. Your answer can be chosen based on what you assume the width to be. Good luck!