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3 years ago

What is the function's range?

Mathematics

1 answer:

BigorU [14]3 years ago

7 0

Answer:

In mathematics, the range of a function may refer to either of two closely related concepts: The codomain of the function The image of the function

Step-by-step explanation:

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Please help me! I will give brainliest and 50 points if all correct!

miss Akunina [59]

Answer:

10. ○ $\displaystyle 4,85; 4\frac{17}{20}$

9. ○680%

8. ○40%

7. ○ $\displaystyle 60$

6. ○0,4, 40,5%, 11⁄25, 4⁄9

5. ○ $\displaystyle 0,928$

4. ○1%

3. ○76%

2. $\displaystyle See\:above\:grid$

1. $\displaystyle See\:above\:grid$

Step-by-step explanation:

10. To convert from a percentage to a decimal, move the decimal mark twice to the left; each 20 is worth 5, and since 5 by 17 is 85, you have your fractional part of 17⁄20, then attach the whole number of 4.

9. To convert from a mixed number\improper fraction to a percentage, first evaluate the fractional part for a decimal answer, then move the decimal mark twice to the right.

8. To convert from a fraction to a percentage, evaluate the fraction for a decimal answer, then move the decimal mark twice to the right.

7. $\displaystyle \frac{132}{220} = \frac{3}{5} =$ 60%

Greatest Common Divisor [GCD]: 44

6. $\displaystyle \frac{11}{25} =$ 44%

$\displaystyle \frac{4}{9} =$ 44,4%

$\displaystyle 0,4 =$ 40%

Now that these are all percentages, it is alot easier to order them from least to greatest.

5. To convert from a percentage to a decimal, move the decimal mark twice to the left.

4. To convert from a decimal to a percentage, move the decimal mark twice to the right.

3. Each 25 is worth 4, and since 4 by 19 is 76, you get 76%.

2. Each 25 is worth 4, and since 4 by 6 is 24, you get 24%, and this graph.

1. Each 36 is worth 2 7⁄9, and since 12 by 2 7⁄9 is 33⅓, you get 33⅓%, so you would choose this answer.

I am joyous to assist you anytime.

8 0

3 years ago

In a quadrilateral ABCD, AB ∥ DC and AD ∥ BC . Find the perimeter of ΔCOD if the diagonals of the quadrilateral intersect each o

SVEN [57.7K]

Answer Perimeter = 33in

Step-by-step explanation:

AC = 20

BD = 20

AB = 13

O is the midpoint

OD = OC = 20/2 = 10

AB = DC = 13 in

P = DC + OD + OC = 13+10+10 = 33in

5 0

3 years ago

)) Omar used 28 centimeters of tape to wrap 4 presents. How much tape will Omar need in

pav-90 [236]

Answer:

He would need 42 cm *or 14cm

Step-by-step explanation:

28/4 is 7

that means that he used 7 cm of tape per present

6 x 7 is 42

that means that he would need 42 cm of tape

4 to 28

6 to 42

*If he already has 4 presents done and he needs to 2 more present then he would need 14 cm, 2 x 7 is 14

8 0

3 years ago

88.83 is what percent of 21

Serjik [45]

88.83 / 21 = 4.23

4.23 is the same number as 423% .

8.23 is 423% of 21.

6 0

3 years ago

Read 2 more answers

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

3 years ago

What is the​ function's range?

What is the function's range?