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andrew11 [14]
3 years ago
14

Please help asap thank you!!

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

No

yes

No

Step-by-step explanation:

yes it is a scalene triangle

the area of the triangle is 28.5

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Math<br><br><br><br> pls help!!<br><br><br><br><br><br> answers?
statuscvo [17]

Answer: Choice B) Infinitely many solutions

  • one solution: x = 8, y = -7/2, z = 0
  • another solution: x = -12, y = 13/2, z = 10

=======================================================

Explanation:

Here's the starting original augmented matrix.

\left[\begin{array}{ccc|c}  1 & 0 & 2 & 8\\5 & 1 & 9 & 73/2\\-4 & 0 & -8 & -32\\\end{array}\right]

We'll multiply everything in row 3 (abbreviated R3) by the value -1/4 or -0.25, which will make that -4 in the first column turn into a 1.

We use this notation to indicate what's going on: (-1/4)*R3 \to R3

That notation says "multiply everything in R3 by -1/4, then replace the old R3 with the new corresponding values".

So we have this next step:

\left[\begin{array}{ccc|c}  1 & 0 & 2 & 8\\5 & 1 & 9 & 73/2\\1 & 0 & 2 & 8\\\end{array}\right]\begin{array}{l}  \ \\\ \\(-1/4)*R3 \to R3\\\end{array}

Notice that the new R3 is perfectly identical to R1.

So we can subtract rows R1 and R3, and replace R3 with the result of nothing but 0's

\left[\begin{array}{ccc|c}  1 & 0 & 2 & 8\\5 & 1 & 9 & 73/2\\0 & 0 & 0 & 0\\\end{array}\right]\begin{array}{l}  \ \\\ \\R3-R1 \to R3\\\end{array}

Whenever you get an entire row of 0's, it <u>always</u> means there are infinitely many solutions.

-------------------

Now let's handle the second row. That 5 needs to turn into a 0. We can multiply R1 by 5, and subtract that from R2.

So we need to compute 5*R1-R2 and have that replace R2.

\left[\begin{array}{ccc|c}  1 & 0 & 2 & 8\\0 & 1 & -1 & -7/2\\0 & 0 & 0 & 0\\\end{array}\right]\begin{array}{l}  \ \\5*R1-R2 \to R2\ \\\ \\\end{array}

Notice that in the third column of R2, we have 9-5*2 = 9-10 = -1. So we have -1 replace the 9. In the fourth column of R2, we have 73/2 - 5*8 = -7/2. So the -7/2 replaces the 73/2.

--------------------

At this point, the augmented matrix is in RREF form. RREF stands for Reduced Row Echelon Form. It seems a bit odd that the "F" of "RREF" stands for "form" even though we say "form" right after "RREF", but I digress.

Because the matrix is in RREF form, this means R1 and R2 lead to these equations:

R1 : 1x+0y+2z = 8\\ R2: 0z+1y-1z = -7/2

which simplify to

R1: x+2z = 8\\R2: y-z = -7/2

Let's get the z terms to each side like so:

x+2z = 8\\x = -2z+8\\\text{ and }\\y-z = -7/2\\y = z-7/2\\

Therefore, all of the solutions are of the form (x,y,z) = (-2z+8, z-7/2, z) where z is any real number.

If z is allowed to be any real number, then we can simply pick any number we want to replace it. We consider z to be the "free variable", in that it's free to be whatever it wants. The values of x and y will depend on what we pick for z.

So the concept of "infinitely many solutions" doesn't exactly mean we can pick just <em>any</em> triple for x,y,z (admittedly it would be nice to randomly pick any 3 numbers off the top of my head and be done right away). Instead, we can pick anything we want for z, and whatever we picked, will directly determine x and y. The x and y are locked into place so to speak.

Let's say we picked z = 0.

That would lead to...

x = -2z+8\\x = -2(0)+8\\x = 8\\\text{ and }\\y = z-7/2\\y = 0-7/2\\y = -7/2\\

So z = 0 would lead to x = 8 and y = -7/2

Rearranging the items in alphabetical order gets us:

x = 8, y = -7/2, z = 0

We have one solution of (x,y,z) = (8, -7/2, 0)

Now let's say we picked z = 10

x = -2z+8\\x = -2(10)+8\\x = -12\\\text{ and }\\y = z-7/2\\y = 10-7/2\\y = 13/2\\

So we have x = -12, y = -13/2, z = 10

Another solution is (x,y,z) = (-12, 13/2, 10)

There's nothing special about z = 0 or z = 10. You can pick any two real numbers you want for z. Just be sure to recalculate the x and y values of course.

To verify each solution, you'll need to plug them back into the original equations formed by the original augmented matrix. After simplifying, you should get the same thing on both sides.

8 0
3 years ago
What is the value of 3-(-2)?
777dan777 [17]

Answer:

5

Step-by-step explanation:

Do the multiplication first:  3 - (-2) becomes 3 + 2.

Thus,

3-(-2) = 5

8 0
3 years ago
Please help asap !!!
denpristay [2]

Answer:

B. x=3/7   y=22/7

C. because it is not precise

D. you need to replace these values in the above equation

<u>Check Understanding</u>

to find the intersection point:

y=y

-3x-2=x-10

solve, x=2

B. by graphing the 2 lines (equations)

Step-by-step explanation:

3 0
3 years ago
What was darios hourly wage ¿
Stella [2.4K]

Answer:

$12 per hour

Step-by-step explanation:

On the graph it shows he earned $24 in 2 hours, so divide how much he earned by two to get the amount he earned in just one.

7 0
3 years ago
Read 2 more answers
Keri is simplifying 5·10^−3.
11111nata11111 [884]

Answer:

1. D

2. A

Step-by-step explanation:

Q1. Kerry is simplifying 5\cdot 10^{-3}

By the definition of negative powers,

a^{-n}=\dfrac{1}{a^n}

Hence,

10^{-3}=\dfrac{1}{10^3}

So, the first step in simplifying the expression is

5\cdot 10^{-3}=5\cdot \dfrac{1}{10^3}

Q2. Given the expression

\dfrac{8}{10^{-2}}

First, use the definition of negative powers:

10^{-2}=\dfrac{1}{10^2}

Thus,

\dfrac{8}{10^-2}=\dfrac{8}{\frac{1}{10^2}}=8\cdot 10^2=8\cdot 100=800

8 0
3 years ago
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