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4vir4ik [10]
3 years ago
7

Hannah's math teacher finds that there's roughly a linear relationship between the amount of time students spend on their homewo

rk and their weekly quiz scores. This relationship can be represented by the equation y=7.1x+55 where y represents the expected quiz score and x represents hours spent on homework that week. What is the meaning of the yy-value when x=1?

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

Expected score with 1 hour of homework

Step-by-step explanation:

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6.7 is 10% of what number
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The temperature is dropping at a rate of five degrees per hour.
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kojo wants to be an author. To improve his writing skills, every day after school he writes 3 pages of a story he is working on.
Aleksandr-060686 [28]

Answer:

(a) 3d=81

(b) 27

Step-by-step explanation:

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<h3>(a) the equation to describe the situation: </h3><h3>3d= 81</h3>

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4 0
2 years ago
Can someone how to get the answer? Thanks! PLEASE HELPpppppppppppppppppppppppp
Over [174]
\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right) \ \textgreater \  \ln \left(6^x\right)=\ln \left(21\right)

\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \  \ln \left(6^x\right)=x\ln \left(6\right)

x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \  \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \  \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)}

Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}

In your case ln means \frac{log 21}{log 6}
5 0
3 years ago
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