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Blababa [14]
3 years ago
15

The diameter of a circle is 34 yards. What is the circle's circumference?

Mathematics
1 answer:
podryga [215]3 years ago
4 0
The circumference is 106.76.
C = dπ
Circumference is diameter times pi(pi equals 3.14)
34 x 3.14 = 106.76
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Factor (4x^3 - 20x^2) -(9x + 45)
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Answer:

u cannot factor it not possible

Step-by-step explanation:

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4 years ago
Question 2 (2 points) Which point is the intersection of the graphs of this system of equations? 6x + 2y = -4 3x +2y = 8
sashaice [31]

Answer:

(x, y) =(-4,10)

Step-by-step explanation:

6x+2y=-4

3x+2y=8 /*(-1)

6x+2y=-4 (1)

-3x-2y=-8 (2)

6x+2x=-4

(1)+(2) 3x=-12

6x+2x=-4

x=-12/3

6x+2y=-4

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6*(-4)+2y=-4

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x=-4

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(x,y)=(-4,10)

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3 years ago
Confused on how to do this help m
pychu [463]

Answer:

Step-by-step explanation:

y=kx,where :k, is the constant

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4 0
3 years ago
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

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Damm [24]
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3 years ago
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