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Blizzard [7]
3 years ago
7

A coordinate plane with 4 lines. The first line is labeled a(x) and passes through (2, negative 4) and (0, 2) and continues past

(negative 1, 5). The second line is labeled f(x) and passes through (negative 6, negative 6), (negative 3, 0), and (0, 6). The third line is labeled g(x) and passes through (negative 2, negative 7), (0, negative 3), (1, negative 1) and (2, 1). The fourth line is labeled h(x) and passes through (negative 6, negative 6), (0, negative 3), and (6, 0). When Janelle woke up, it was –3 degrees Fahrenheit outside. As the morning progressed, the temperature rose 2 degrees every hour. Which line on the graph could represent this scenario? a(x) f(x) g(x) h(x)
Mathematics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

the answer is g(x)

Step-by-step explanation:

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An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
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Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


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