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2 years ago

8c^(2)+6c-2c^(2)-5c

Mathematics

1 answer:

iren [92.7K]2 years ago

6 0

Answer:

6c^2 + c

Step-by-step explanation:

8^2 - 2c^2= 6c^2

6c-5c = c

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Jiao is a chinese student visiting family in the united states. she spent $79 on dinner for her family one evening. if the excha

bogdanovich [222]

Answer:

That day Jiao spent $CNY 514.29.

Step-by-step explanation:

Given that Jiao is a Chinese student visiting family in the United States, and she spent $ 79 on dinner for her family one evening, if the exchange rate that day is UDS to CNY = 6.51, to determine approximately how much money did she spend in CNY the following calculation must be performed:

79 x 6.51 = X

514.29 = X

Therefore, that day Jiao spent $ CNY 514.29.

6 0

3 years ago

The solution set for <br> 6a^2-a-5=0

Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30 =-6(5)

b=-1 =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0

3 years ago

Pls can someone help (marking branliest)

Serhud [2]

Answer:

about 46 shopper receive the free earbuds

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3 years ago

Suppose at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard. Also, 30% of the

Doss [256]

Answer:

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

$= P(B') = 1-0.4 =0.6$

2. the probability that this student has either a Visa card or a MasterCard.

= $P(AUB) = 0.70$

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

= $P(AUB)' = 0.30$

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

6 0

3 years ago

Mandy used the input and output in this table to write ratios. She concluded that because that they are not all equivalent, this

wolverine [178]

The problem is stating that Mandy found the ratio between input and output of many points on the graph, which are displayed by the fractions. Mandy's conclusion was that they were not equivalent, meaning they were different and that is why the function is not proportional. Mandy's conclusion is wrong, the relation is proportional. If we take all the functions we have:

$\frac{5}{1}=\frac{10}{2}=\frac{25}{5}=\frac{50}{10}$

Where the input is the denominator and the output is the numerator we will have a ratio of "5". Mandy's mistake was to invert the last fraction, she inserted the output in the denominator, this is why she said the were different.

6 0

1 year ago