Answer:
8280 cal
Step-by-step explanation:
Q=mc(delta)T
Q=1200(0.115)(-60)
Q=8280 cal
I used 1200 g instead of 1.2 kg
<span>3/4(4c+16)=2c+9
We simplify the equation to the form, which is simple to understand
<span>3/4(4c+16)=2c+9
Reorder the terms in parentheses
<span>+(+3c+12)=2c+9
Remove unnecessary parentheses
<span>+3c+12=+2c+9
We move all terms containing c to the left and all other terms to the right.
<span>+3c-2c=+9-12
We simplify left and right side of the equation.
<span>+1c=-3
We divide both sides of the equation by 1 to get c.
<span>c=-3
Hope this helped! :)
</span></span></span></span></span></span></span>
Answer:
58+40e−t/2458+40e−t/24
step by step explanation:
Normally, the temperature of a corpse is the temperature of the surrounding environment.
This is done by losing or gaining heat to equilibrate to that of the surrounding.
Let's assume that the final temperature of the corpse is after t hrs.
Then the temperature of the surrounding in degree Fahrenheit is equal to 58+40e−t/2458+40e−t/24
Uhh 27 not really sure tbh
Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
