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valkas [14]
2 years ago
13

In ΔTUV, v = 240 inches, t = 390 inches and ∠U=71°. Find the area of ΔTUV, to the nearest square inch.

Mathematics
1 answer:
meriva2 years ago
7 0

Answer:

44250

Step-by-step explanation:

delta math

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Kristin has 4 more headbands than Nikki does.
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Answer:

(h+4)

Step-by-step explanation:

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Jose bought 1.5 pounds of apples for $3.60. How much would 34 of a pound of apples cost?
uysha [10]
122.4$ hope it helps !!!
6 0
3 years ago
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How do I factor this? <br> 5x^2y+45x^3y^2
ruslelena [56]

Answer:

5 x^2 y (9 x y + 1)

Step-by-step explanation:

Factor the following:

45 x^3 y^2 + 5 x^2 y

Factor common terms out of 45 x^3 y^2 + 5 x^2 y.

Factor 5 x^2 y out of 45 x^3 y^2 + 5 x^2 y:

Answer: 5 x^2 y (9 x y + 1)

8 0
2 years ago
The number of students who chose lunch was 5 more than the number of students who chose breakfast. Write a system of linear equa
Papessa [141]

Answer:

The system of linear equations are y=5+x and  x+y=25

Step-by-step explanation:

Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.

(50 students picked, 25 picked dinner the rest picked lunch and breakfast)

To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?

Solution :

The number of students who chose breakfast be 'x'

The number of students who chose lunch be 'y'.

The number of students who chose lunch was 5 more than the number of students who chose breakfast.

i.e. y=5+x

Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.

So, x+y=25

Therefore, the system of linear equations are y=5+x and  x+y=25

4 0
3 years ago
HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

  = (1/2)((3a -1) +(3·4 -1))(4 -a)

  = (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

  12 = (1/2)(3a +10)(4 -a)

 24 = (3a +10)(4 -a) = -3a² +2a +40

  3a² -2a -16 = 0 . . . . . . subtract the right side

  (3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

  a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

_____

<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

5 0
3 years ago
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