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Andrew [12]
2 years ago
11

A triangle with a base of 10 and side lengths of 13 is similar to what other kind of triangle

Mathematics
1 answer:
fgiga [73]2 years ago
6 0

Answer:

Step-by-step explanation:

the only correct choice is C

= multiplied each side by 2.5

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5:17pm

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A bag of marbles contains 4 green, 3 blue, 2 red, and 5 yellow marbles. How many total possible outcomes are when choosing a mar
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Square root of 144 X^7 Y^5
LekaFEV [45]
The first step to solving this is to factor out the first perfect square
\sqrt{12^{2} x^{7} y^{5}   }
now factor out the second perfect square
\sqrt{ 12^{2} x^{6} X x  y^{5}  }
then factor out the second perfect square 
\sqrt{ 12^{2}  x^{6} X x  y^{4} X y}
the root of a product is equal to the product of the roots of each factor
\sqrt{ 12^{2} } \sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the first square root
12\sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the second square root
12x³\sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the third square root
12x³y²\sqrt{xy}
this means that the correct answer to your question is 12x³y²\sqrt{xy} .
let me know if you have any further questions
:)
4 0
3 years ago
A simple linear regression analysis was conducted to predict the Exam 3 score of students in STA 2023 based on their Exam 1 scor
Tju [1.3M]

Answer:

Option 3) The expected Exam 3 score for someone that made a 0 on Exam 1 is a 50.57.            

Step-by-step explanation:

We are given the following in the question:

\hat{y}(x) = 50.57+0.4845x

The above equation is a linear regression equation  to predict the Exam 3 score of students in STA 2023 based on their Exam 1 score.

\hat{y}: The dependent variable, Exam 3 score

x: The independent variable, Exam 1 score

Comparing to general linear equation,

y = mx + c

We get,

m = 0.4845, c = 50.57

where

c is the y - intercept and the score in exam 3 when exam score is 0.

\hat{y}(0) = 50.57+0.4845(0)\\\hat{y}(0) = 50.57

m is the slope and tells us about the rate of change.

When exam 1 grade is increased by 1, we can write,

\hat{y}(x) = 50.57+0.4845x\\\hat{y}(x+1) = 50.57+0.4845(x+1)\\\hat{y}(x+1)-\hat{y}(x) = 50.57+0.4845(x+1)-( 50.57+0.4845x)\\\hat{y}(x+1)-\hat{y}(x) = 0.4845(x+1-x)\\\hat{y}(x+1)-\hat{y}(x) = 0.4845

Thus, the y-intercept for the given equation can be interpreted as

Option 3) The expected Exam 3 score for someone that made a 0 on Exam 1 is a 50.57.

6 0
3 years ago
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