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vova2212 [387]
3 years ago
6

What is the simplified form of the rational expression below? SX c. 8( Yun? D. 8(**)

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer: The answer is (5(x-1))/3x

Step-by-step explanation:

5x² - 5/ 3x² + 3x

= 5(x+1)(x-1) all over 3x(x+1)

= 5x - 5 over 3x

Hope this info helps

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Please solve with steps
Bad White [126]

Answer:

GOOD LUCK HOPE YOU FOUND YOUR ANSWER

Step-by-step explanation:

3 0
3 years ago
Is this a function? <br> A) yes<br> B) No
Lelu [443]
Don’t listen to get the links they are annoying
6 0
3 years ago
I NEED HELP IDENTIFYING THE SLOPE PLEASE !!! Pic attatched !!!!
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 2,4 ) and (x₂, y₂ ) = (5, 1)

m = \frac{1-4}{5-2}  = \frac{-3}{3} = - 1 ← negative slope

Repeat

with (x₁, y₁ ) = - 7,8) and (x₂, y₂ ) = (- 7, 0)

m = \frac{0-8}{-7+7} = \frac{-8}{0}

Division by zero is undefined, thus slope is undefined.

Repeat with

(x₁, y₁ ) = (6, - 3) and (x₂, y₂ ) = (- 4, - 3)

m = \frac{-3+3}{-4-6} = \frac{0}{-10} = 0 ← zero slope

Repeat with

(x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (- 1, 2)

m = \frac{2-5}{-1-3} = \frac{-3}{-4} = \frac{3}{4} ← positive slope

7 0
3 years ago
Mikey has two mice that were about the same age and weight Mikey fed each of the 2 mice a different feed for a month. He measure
Nadusha1986 [10]
The following is the rest of the question:
------------------------------------------------------
Mikey's results showed that although both mice gained weight over the month, mouse 2 gained more weight than mouse 1.Which graph below best shows these results?
The complete figure is attached
=========================================================
Solution:
---------------
Graph (1)⇒⇒⇒ mouse 2 has constant weight and mouse 1 gained weight

Graph (3)⇒⇒⇒ mouse 2 has did not gain weight and mouse 1 gained weight

∴ Graph (1) and (3) are incorrect because both mice gained weight .

Graph (4) is incorrect because mouse 2 gained more weight than mouse 1

So, the correct answer is graph (2)







5 0
3 years ago
Read 2 more answers
2. Which of the following equations are perpendicular to 2y = -3x + 1 I. II. III. y=-x-1 - 2x + 3y = -5 2x + 3y = 2 (A) I only (
Novay_Z [31]

The equation in given as ;

2y = -3x + 1

This can be written as ;

y= -3/2 x + 1/2

This means the equation has a gradient of -3/2

Let this slope , be , ---------m1

For perperdicular lines , the product of their slopes = -1 .This means if the other line has a gradient of m2 then : m1 * m2 = -1

So from the answers :

i) y= 2/3 x - 1 the slope is 2/3

m2 = 2/3

m1 * m2 = -1 -------check the if this is true by using the two values of gradient as;

-3/2 * 2/3 = - 1 ------ This is true-----equation i

II.

-2x + 3y = -5

3y = 2x -5

y= 2/3 x -5/3 -----m2 here is 2/3

m1*m2 = -1

-3/2 * 2/3 = -1 -----this is true , so ----equation ii

iii)

2x + 3y = 2

3y = -2x + 2

y= -2/3 x + 2/3 -----m2 = -2/3

m1*m2 = -1

-3/2 * -2/3 = 1 -----this is not true,,,equation iii is not perpendicular to our equation.

so, equation i and ii are perpendicular to our equation .

Answer : B i and ii only

4 0
1 year ago
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