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ziro4ka [17]
2 years ago
14

Can you define for me what a factor is

Mathematics
2 answers:
blondinia [14]2 years ago
4 0

Answer:

An integer that divides into another integer exactly is called a Factor.

Step-by-step explanation:


maw [93]2 years ago
4 0

Answer:

A number that results in an exact number when divided by another.

Step-by-step explanation:

In other words, given x is a whole (exact) number:

y / z = x → which can be also written with numbers, for example → 8 / 4 = 2



Hope it helped,


BioTeacher101

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The length of a rectangle is three more than twice its width the perimeter of a rectangle is 42 cm what is the length of the rec
Maurinko [17]

Answer:

The length of the rectangle is 15 cm.

Step-by-step explanation:

breadth(b)=?

length(l)= 3+2b

perimeter(P)= 42 cm

Now,

  P = 2 ( l+b )

or, 42= 2 ( 3+2b+b)

or, 42 = 2 ( 3+3b)

or, \frac{42}{2} = 3+3b

or, 21 = 3+3b

or, 21-3 =3b

or, 18 = 3b

or, \frac{18}{3} = b

or, 6 = b

Here, Breadth(b)= 6 cm

Length (l) = 3 + 2*6

              = 3 + 12

              =15 cm

5 0
3 years ago
Mr. Ferguson's classroom is 30 ft long, 20 ft wide, and 10 ft tall. There are 3 concrete
Anna [14]

Answer:

they all went to the stairs

Step-by-step explanation:

67.90 I don't know u tell me

6 0
3 years ago
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
3 years ago
The vertex of the graph of f(x) = |x - 3| +6 is located at<br> Done<br> Intro
Igoryamba

Answer:

The vertex of the graph is located at the point (3,6)

Step-by-step explanation:

Here, we want to know where the vertex of the equation if plotted will be

To get this, what we have to do is to equate the expression that we have in the absolute value to zero

After this, we then proceed to solve for the value of x

We have this as;

x -3 = 0

hence;

x = 0 + 3

x = 3

to get the y-value of the vertex, we look at the value at the side of the absolute value

This value is 6 and thus, the y-value of the vertex point is 6

So the coordinates of the vertex is (3,6)

8 0
2 years ago
Can you find x I don’t know how.
kodGreya [7K]

Answer:

7

Step-by-step explanation:

(x+3)/(x+8) = 2/3

3x + 9 = 2x + 16

x = 7

8 0
3 years ago
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