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bonufazy [111]
3 years ago
5

Evaluate 15r -1 when r=5

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

74

Step-by-step explanation:

You just have to substitute r with 5.

Now, the equation looks like this:

15(5)-1

Next, solve 15*5 first according to PEMDAS

And 15*5 equals 75

\frac{\left[\begin{array}{ccc}1&5\\5\\\end{array}\right] }{75}

Lastly, do 75-1 which equals 74

\frac{\left[\begin{array}{ccc}7&5\\-1\\\end{array}\right] }{74}

Therefore, 74 is your answer.

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Answer:

D. (3, 4, 5)

Step-by-step explanation:

5 =  \sqrt{ {(3)}^{2}  +  {(4)}^{2} }  \\ 5 =  \sqrt{9 + 16}  \\ 5 =  \sqrt{25 }  \\ 5 = 5

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3 years ago
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The answer is D! Hope you have a great day!

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Andrej [43]

Answer:

x=78

Step-by-step explanation:

q is 90 degrees since it is a right angle,

p=12

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3 years ago
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Katrina has the option of an 8-year non-subsidized student loan of $32,000 at an annual interest rate of 3.5% or an 8-year subsi
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Answer: katrina will pay less interest on the 8-year non subsidized student loan

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Subsidized loan at 4.5% for 8years will be 4.5/100 × 32000 x 1/12= USD120/month, USD 1440/year. For 8 years, USD11,520

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3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
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<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
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