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bonufazy [111]
3 years ago
5

Evaluate 15r -1 when r=5

Mathematics
1 answer:
alukav5142 [94]3 years ago
3 0

Answer:

74

Step-by-step explanation:

You just have to substitute r with 5.

Now, the equation looks like this:

15(5)-1

Next, solve 15*5 first according to PEMDAS

And 15*5 equals 75

\frac{\left[\begin{array}{ccc}1&5\\5\\\end{array}\right] }{75}

Lastly, do 75-1 which equals 74

\frac{\left[\begin{array}{ccc}7&5\\-1\\\end{array}\right] }{74}

Therefore, 74 is your answer.

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Annual high temperatures in a certain location have been tracked for several years. Let
stiks02 [169]

Answer:

Y= 19.86 - 0.42b

Step-by-step explanation:

Step 1: Write the formula

Regression Line: Y = a + bx

a=<u>(Total Y) x (Total X^2) - (Total X) x (Total XY)</u>

                    n x (total X^2) - (Total X)^2

b= <u>n x (Total XY) - (Total X) x (Total Y)</u>

             n x (total X^2) - (Total X)^2    

Step 2: Make a table to find all values

X  Y          X^2    Y^2               XY

5 17.19 25 295.4961       85.95

6 19.12 36 365.5744       114.72

7 16.75 49 280.5625      117.25

8 15.58 64 242.7364       124.64

9 16.21 81 262.7641        145.89

10 14.14 100 199.9396        141.1

11 14.97 121 224.1009        164.67

12 16.2         144 262.44            194.4

68 130.16     620  2133.614       1088.62              TOTAL

Step 3: Substitute all values in the equation to find a and b

a=<u>(Total Y) x (Total X^2) - (Total X) x (Total XY)</u>

                    n x (total X^2) - (Total X)^2

a= <u>(130.16 x 620) - (68 x 1088.62)</u>

                     8 x (620) - (68)^2

a = <u>80699.2 - 74026.16</u>

                336

a = 19.86

b = <u>n x (Total XY) - (Total X) x (Total Y)</u>

             n x (total X^2) - (Total X)^2    

b = <u>8 x (1088.62) - (68 x 130.16)</u>

             8 x (620) - (68)^2

b =<u> 8708.96 - 8850.88 </u>

                336

b = -0.42

Step 4 : Apply values of a and b in the formula of the regression line.

Regression Line: Y = a + bx

Y= 19.86 + b (-0.42)

Y= 19.86 - 0.42b

8 0
3 years ago
Please answer! It would be appreciated if work is also shown!
borishaifa [10]

Quantity of paint left = \frac{389}{480} gallons

Solution:

Quantity of yellow paint = 1\frac{1}{5}=\frac{6}{5} gallons

Quantity of green paint = 1\frac{1}{6}=\frac{7}{6} gallons

Quantity of blue paint = \frac{7}{8} gallons

Quantity of paint used = \frac{3}{4} gallons of each paint

Quantity of paint left = 1-\frac{3}{4}=\frac{1}{4} gallons of each paint

Quantity of paint left = (\frac{6}{5}+\frac{7}{6}+\frac{7}{8})\times\frac{1}{4}

Taking LCM for 5, 6, 8, we get LCM = 120

(\frac{6}{5}+\frac{7}{6}+\frac{7}{8})\times\frac{1}{4}=(\frac{144}{120}+\frac{140}{120}+\frac{105}{120})\times\frac{1}{4}

                         =(\frac{389}{120})\times\frac{1}{4}

                         =\frac{389}{480}

Hence, Mark will have \frac{389}{480} gallons of paint left after painting the mural.

3 0
3 years ago
If I were to start with $50 and add $20 each week for 12 weeks, what is an equation that represents the relationship between the
ExtremeBDS [4]

Answer:

This is a function y = mx + b:

  • You start with $50, so the y-intercept(b) is 50.
  • Adding $20 a week means that the slope(m) is 20.

So, the function would be y = 20x + 50, where y is the dollar amount after x weeks and x cannot be greater than 12.

8 0
1 year ago
Solve for the equation below<br><br> 4x^n + x^4n = ?
slavikrds [6]
4x + 6 = -10<span>Simplifying 4x + 6 = -10 Reorder the terms: 6 + 4x = -10 Solving 6 + 4x = -10 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + 4x = -10 + -6 Combine like terms: 6 + -6 = 0 0 + 4x = -10 + -6 4x = -10 + -6 Combine like terms: -10 + -6 = -16 4x = -16 Divide each side by '4'. x = -4 Simplifying x = -4</span>
7 0
3 years ago
Please give me the answer and show me how you solved it
mixer [17]

on number 5 question the answer is 4,5,9

Step-by-step explanation:

it is because a right triangle is composed of 3 different sides (hypothenus, opposite angle and adjacent angle)

3 0
3 years ago
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